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2 years ago

If there are 10 values in a data set, in order from smallest to largest, what is

Mathematics

2 answers:

8090 [49]2 years ago

8 0

Answer:

If you meant median, the median would be the data in the middle.

Step-by-step explanation:

In this case, 1-2-3-4-5 (here) 6-7-8-9-10

5.5 would be in the middle because there is an even amount of numbers.

OlgaM077 [116]2 years ago

6 0

Answer:

B.the mean of the 5th and 6th values

Step-by-step explanation:

apexs

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Suppose that you are asked to conduct a study to determine whether smaller class

weeeeeb [17]

Answer:

a. correlation

b. inverse linear correlation exists If the higher the population of students lead to a decrease in test score,

c. yes

Step-by-step explanation:

a. Correlation is a measure of the amount of association existing between two variables.

b. For linear correlation, if points are plotted on a graph and all the points lie on a straight line, then perfect linear correlation is said to exist. When a straight line having a positive gradient can reasonably be drawn through points on a graph positive or direct linear correlation exists,

Similarly,when a straight line having a negative gradient can reasonably be drawn through points on a graph, negative or inverse linear correlation exists,

The results of this determination give values of r lying between +1 and −1, where +1 indicates perfect direct Positive linear correlation and −1 indicates perfect inverse correlation or Negative linear correlation and 0 indicates that no correlation exists.

If the higher the population of students lead to a decrease in test score, there will definitely be a negative correlation between class size and test score. i.e low class size result in high test score which consequently lead to high performance.

c. YES

A negative correlation means low class size result in high test score which consequently lead to better performance.

8 0

3 years ago

Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation option

denis-greek [22]

Answer:

The probability that he teleports at least once a day = $\mathbf{\frac{5}{9}}$

Step-by-step explanation:

Given -

Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation options teleport ride a dragon or walk to work and in the evening he has the same three choices for his trip home.

Total no of outcomes = 3

P( He not choose teleport in the morning ) = $\frac{2}{3}$

P( He not choose teleport in the evening ) = $\frac{2}{3}$

P ( he choose teleports at least once a day ) = 1 - P ( he not choose teleports in a day )

= 1 - P( He not choose teleport in the morning ) $\times$ P( He not choose teleport in the evening )

= $1 - \frac{2}{3}\times\frac{2}{3}$

= $\frac{5}{9}$

3 0

3 years ago

The difference of d minus 3 divided by 2

Eduardwww [97]

Answer:

(d-3)/2

Step-by-step explanation:

Difference is subtraction

(d-3)/2

6 0

2 years ago

Mr. Crow, the head groundskeeper at High Tech Middle School, mows the lawn along the side of the gym. The lawn is rectangular, a

Bogdan [553]

Answer:

Dimensions, Length = 85 feet and Width = 40 feet

Area of lawn = 3400 $feet^2$

Step-by-step explanation:

Given: Lawn is rectangular in shape

Length of lawn is 5 feet more than twice its breath/width

Perimeter of Lawn = 250 feet

To find: (a) Length and width of lawn

(b) Area of Lawn

First let the a variable for width/breadth. Say, Width = b.

So, the length of lawn = 2b + 5

Perimeter of Rectangle = 2 × ( length + width )

Now, substitue given values in this formula

∴ Perimeter of Lawn = 2 × ( 2b + 5 + b )

$250 = 2\times{(2b+b+5)}\\250= 2\times{(3b+5)}\\3b+5 = \frac{250}{2}\\3b = 125 -5\\3b = 120\\b=\frac{120}{3}\\b=40$

∴width = 40 feet

⇒ length = 85 feet

Now we find are of lawn using formula of area of rectangle

Area of lawn = length × width

= 85 × 40

= 3400 $feet^2$

Dimensions, Length = 85 feet and Width = 40 feet

Area of lawn = 3400 $feet^2$

7 0

3 years ago

The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
\\
\\\frac{d}{dx}y^2 + \frac{d}{dx}(xy+1)^3 = \frac{d}{dx}0
\\
\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
\\
\\y' = \frac{-3(4)(-1) -6(2)(1)+3}{(6 +6(4)(-1)+3(4)(-1)-2 )}
\\
\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
\\
\\y' = \frac{3}{( -32 )}$

7 0

2 years ago