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WARRIOR [948]
3 years ago
10

These are the first six terms of a sequence with a = 2:

Mathematics
1 answer:
inn [45]3 years ago
7 0

Answer:

a_{n} = 9a_{n-1}

Step-by-step explanation:

Note there is a common ratio r between consecutive terms of the sequence, that is

r = 18 ÷ 2 = 162 ÷ 18 = 1458 ÷ 162 = 13122 ÷ 1458 = 9

A recursive formula allows a term in the sequence to be found by multiplying the previous term by the common ratio, that is

a_{n} = 9a_{n-1} with a₁ = 2

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Rico and Josh took off on skateboards going in the same direction. After 20min, Rico had traveled 5.98 kilometers and Josh had g
Alisiya [41]

Answer:

2.22 km

Step-by-step explanation:

Assuming initially both were at the same point ...

Distance from Rico = 5.98 km.

Distance from Josh = 8.2 km in the same direction.

If they were going in the same direction, then the final distance between the two can be written as follows:

d = 8.2 - 5.98 = 2.22 km

After 20 minutes, Rico and Josh were 2.22 km away. of distance between them.

7 0
3 years ago
6. Carla runs 3 miles in 30 minutes.
NARA [144]

Answer:

Carla ran 0.1 miles per minute.

Step-by-step explanation:

To solve this, we need to use the distance formula.

The formula is d=rt, where d is the distance traveled, r is the rate in which the distance is traveled, and t is the amount of time it took to go that distance. So lets plug it all in.

d=rt

3=(r)(30)

Now, we need to do the inverse of multiplying 30 to both sides, which would be the same as dividing by 30 on both sides.

3/30=(r)(30/30)

0.1=r

The rate is 0.1. Carla ran 0.1 miles per minute.

3 0
2 years ago
Inequalities!
kari74 [83]
Is there a picture!
8 0
3 years ago
Read 2 more answers
Write 4.14 in a fractional notation ?
tatiyna
If it's in a fraction you want it it's 207/50 irregular
And 4 7/50 as a mixed fraction
3 0
3 years ago
Suppose you have a right triangle area marked in the ground with a base (8-h) meters long and a height h meters long. the hypote
Aleks [24]

Answer:

5.415m and 2.585m long

Step-by-step explanation:

For a right triangle

hyp^2 = opp^2 + adj^2 (Pythagoras theorem)

Given

hypotenuse = 6m

height(opposite) = h meters

Adjacent = (8-h)m

Substitute into the expression above;

6² = h²+(8-h)²

36 = h²+64-16h+h²

36 = 2h²-16h+64

2h²-16h+64-36 = 0

2h²-16h+28= 0

Divide through by 2

h²-8h+14 = 0

Using the general formula

h = 8±√8²-4(14)/2

h = 8±√64-56/2

h = 8±√8/2

h = 8±2.83/2

h = 8+2.83/2 and 8-2.83/2

h = 10.83/2 and 5.17/2

h = 5.415 and 2.585

hence the length of the height of the right triangle are 5.415m and 2.585m long

7 0
3 years ago
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