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love history [14]
3 years ago
14

Miri counted her money and found that her 25 coins which were nickels, dimes, and quarters were worth $3.20. the number of dimes

exceeded the number of nickels by 4. how many coins of each kind did she have?
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
4 0
Nickels = x

dimes = x + 4

quarters = x

Value of coins:

nickel = 5 cents

dime = 10 cents

quarter = 25 cents

5x + 10(x + 4) + 25x = 3.20

5x + 10x + 40 + 25x = 320

40x = 320 - 40

40x = 280

x = 280/40

x = 7

There are 7 quarters, 7 nickels and 11 dimes.



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