Answer:
- Hence, 75.52 percent of the u.s. population had internet access in 2005.
- After 25 years or in the year 2015 89% have internet access.
Step-by-step explanation:
the percent p of the u.s. population with internet access is given by:
25 p-34 t=1378
where t is the number of years after 1990.
- We are asked to find what percent of the u.s. population had internet access in 2005 i.e. we need to find the value of p after 15 years i.e. t=15.
⇒ 25p-34×(15)=1378
⇒ 25p-510=1378
⇒ 25p=1378+510
⇒ 25p=1888
⇒ p=75.52
Hence, 75.52 percent of the u.s. population had internet access in 2005.
- Next we are asked to find in what year will 89% have internet access?
i.e. we have to find the value of t when we are given p=89
⇒ 25×89-34t=1378
⇒ 2225-34t=1378
⇒ 2225-1378=34t
⇒ 847=34t
⇒ or 34t=847
⇒ t=24.9112≈25
Hence after 25 years 89% will have internet access.
i.e. in the year 2015 89% will have internet access.
Answer:
13+8x
Step-by-step explanation:
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Hello
Please tell in English I don’t understand
Answer:
Step-by-step explanation:
This is a binomial probability problem. There are only two outcomes. It is either a chosen person has immunity to a particular disease or he does not. The probability of success in this case, p is the probability that a chosen person has immunity to a particular disease. Thus
p = 0.6
The probability of failure, q is q = 1 - p
Thus, q = 1 - 0.6 = 0.4
Mean = np
Where n represents sample size. Thus,
Mean = 12 × 0.6 = 7.2
599×1.3 should give you your answer
