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Luden [163]
3 years ago
13

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
8 0

-2<em>x</em> + 6<em>y</em> = -38

3<em>x</em> - 4<em>y</em> = 32

To solve by elimination, multiply the top equation by 3 and the bottom equation by 2.

3(-2<em>x</em> + 6<em>y</em> = -38) --> -6<em>x</em> + 18<em>y</em> = -114

2(3<em>x</em> - 4<em>y</em> = 32) --> 6<em>x</em> - 8<em>y</em> = 64

Add the equations.

-6<em>x </em>+ 18<em>y</em> = -114

6<em>x</em> - 8<em>y</em> = 64

+_____________

0 + 10<em>y</em> = -50

10<em>y</em> = -50

<em>y</em> = -5

Substitute -5 for y into one of the original equations to find x.

3<em>x</em> - 4<em>y</em> = 32

3<em>x</em> - 4(-5) = 32

3<em>x</em> + 20 = 32

3<em>x</em> = 12

<em>x</em> = 4

Check work by plugging the <em>x</em>- and <em>y</em>-values into both of the original equations.

-2<em>x</em> + 6<em>y</em> = -38

-2(4) + 6(-5) = -38

-8 - 30 = 38

38 = 38


3<em>x</em> - 4<em>y</em> = 32

3(4) - 4(-5) = 32

12 + 20 = 32

32 = 32

Answer:

<em>x</em> = 4 and <em>y</em> = -5; (4, -5).

romanna [79]3 years ago
8 0

I'll be using the substitution method, so firstly, subtract 6y on both sides of the first equation: -2x=-6y-38

Next, divide by -2 on both sides of the first equation: x=3y+19

Now substitute x in the second equation with (3y + 19) to solve for y as such:

3(3y+19)-4y=32\\ 9y+57-4y=32\\ 5y+57=32\\ 5y=-25\\ y=-5

Now that we have the value of y, substitute it in either equation to solve for x:

-2x+6(-5)=-38\\ -2x-30=-38\\ -2x=-8\\ x=4\\ \\ 3x-4(-5)=32\\ 3x+20=32\\ 3x=12\\ x=4

<em>In short, your solution is (4, -5), or the first option.</em>

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