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boyakko [2]
2 years ago
13

FS Math FS LV2 Volume Problems Q1. The swimming pool is in the shape of a cuboid 20 metres long and 8 metres wide. It is filled

with water to a depth of 1.8 metres. Diagram not accurately drawn 1.8m 8 m 20m Charles needs to add chlorine powder to the water in the pool to keep the water clean. Each week Charles needs to use 300 grams of chlorine powder per 50 m of water. Chlorine powder is sold in boxes. Each box contains 5000 grams of chlorine powder. Charles thinks that one box will be enough for 4 weeks. Is one box enough for 4 weeks? Show why you think this.
pls answer
​
Mathematics
1 answer:
DedPeter [7]2 years ago
3 0

From the volume computed, since each box contains 5000 grams of chlorine powder, it won't be enough for 4 weeks.

<h3>How to calculate the volume</h3>

The volume of the swimming pool water will be:

= length × width × height.

= 20 × 8 × 1.8

= 288m³

Since 50m³ of water chlorine needs 300gm, therefore, 1m³ will need;

= 300/50 = 6

Therefore, 288m³ will need:

= 288 × 6 = 1728gm

The amount of chlorine powder needed for 4 weeks will be:

= 1728 × 4

= 6912 gm

Since each box contains 5000 grams of chlorine powder, it won't be enough for 4 weeks.

Learn more about volume on:

brainly.com/question/1972490

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CALCULATE

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The length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapezoid has a height of
ycow [4]

The length of the longer base is 41 ft.

<u><em>Explanation</em></u>

Lets assume, length of one base is x ft.

As, another base is 19 less than five times the length of this base, so the length of another base = (5x- 19) ft.

The trapezoid has a height of 18 ft and area of 477 ft²

Formula for Area of trapezoid, A=\frac{1}{2} (a+b)*h , where a, b = Two bases of trapezoid and h = height of the trapezoid.

Given in the question: A= 477 and h= 18

We have also two bases as: a= x and b= 5x-19

So, according to the above formula...

A= \frac{1}{2}(a+b)h\\\\ 477=\frac{1}{2}(x+5x-19)*18\\\\ 477=9(6x-19)\\\\477= 54x-171\\\\477+171=54x\\\\648=54x\\\\x=\frac{648}{54} = 12

So, length of one base is 12 ft  and another base =(5*12-19)ft =(60-19)ft = 41 ft

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8 0
3 years ago
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