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beks73 [17]
3 years ago
9

Billy is walking from the front door of his house to his bus stop, which is 960 feet away from his front door. As Billy walks ou

t his front door, he walks in a straight path toward his bus stop at a constant rate of 7.5 feet per second.
(A) Illustrate the situation with a diagram and define variables to represent the values of the relevant varying quantitities. (Label the variables on your picture.)
(B) Define a function f to determine Billy's distance from his bus stop in terms of the number of seconds he has been walking.
(C) What is the independent quantity and what is the domain of f (the values the independent quantity can take on)?
(D) What is the dependent quantity and what is the range of f (the values the dependent quantity can take on)?
(E) What do each of the following represent: f(0) and f(60.25)?

Mathematics
1 answer:
sasho [114]3 years ago
4 0

Answer:

b) 690 - 7.5*t

c) 0 < t < 92s time (t) is independent quantity

d) 0 < s < 690ft distance from bus stop (s) is dependent quantity

e) f(0) = 690 ft away from bus stop , f(60.25) = 238.125 ft away from bus stop

Step-by-step explanation:

Part a - see diagram

part b

initial distance from bus stop s0 = 690 ft

distance covered = 7.5*t

s = s0 - distance covered

s = 690 - 7.5*t = f(t)

part c

s = 0 or s = 690

0 = 690 -7.5*t

t = 92 s

Hence domain : 0 < t < 92s time (t) is independent quantity

part d

s = 0 or s = 690

Hence range : 0 < s < 690ft distance from bus stop (s) is dependent quantity because it depends on time (t)

part e

f(0) is s @t = 0

f(0) = 690 ft away from bus stop

f(60.25) is s @t = 60.25

f(60.25) = 690 - 7.5*60.25 = 238.125 ft away from bus stop.

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