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kenny6666 [7]
3 years ago
5

How do you solve 2h(h+7)?

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
6 0
To solve 2h(h+7), you will first multiply each term in the parenthesis by 2 h
2h x h + 2h x 7
Now you will take "2h x h", and calculate the product. this will give you 2h to the 2nd power, or 2h^2
2h^2 + 2h x 7
now you will calculate the product of "2h x 7". this will give you 14h
this makes your answer:
2h^2 + 14h
:)
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16k-100k polynomial
Alexeev081 [22]
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3 years ago
1 Lindsay has finished 14 of the 20 lessons in her violin book.
Studentka2010 [4]

Answer:

21 questions out of 30

6 0
3 years ago
Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on
jolli1 [7]

Answer:

See explanation

Step-by-step explanation:

<h3 /><h3>Step 1</h3>

Miguel wins $2 is if he pulls two chips with the number 1.  

<u>Probability of winning is: </u>

  • 2/4 * 1/3 = 1/6  as there are 4 chips in total

<u> Probability of loosing is:</u>

  • 1- 1/6 = 5/6
<h3 /><h3>Step 2</h3>

<u>Missing values we found in the step 1, can be populated in the table:</u>

  • Xi === 2 === -1
  • P(Xi) === 1/6 === 5/6

<u>Expected Value as per table data:</u>

  • 1/6*2 + 5/6*(-1) = -1/2

Expected value is $1/2 loss each time he plays

<h3 /><h3>Step 3</h3>

To make the game fair, the expected value should be zero.

<u>Then as per the calculation above, let's replace 2, with x, and find its value.</u>

  • 1/6x + 5/6*(-1) = 0      
  • 1/6x = 5/6                  
  • x= 5  

So the amount should be $5 to make the game fair.

6 0
3 years ago
Figure ABCD is a parallelogram with point C (3, -2). What rule would rotate the figure 90 degrees clockwise, and what coordinate
WITCHER [35]
      Coordinates of C ( 3, - 2 ). After the rotation for 90° clockwise new coordinates would be C ` ( - 2, - 3 ).
      Answer:
      B ) ( x , y ) → ( y, -x ) ;   C`( -2, - 3 )  
4 0
3 years ago
Read 2 more answers
Evaluate the function rule to find the range of each function for the domain {-3, 0, 5}. f(x) = x² − 6x + 4
harina [27]
Range is output for given input

domain is D={-3,0,5}
input -3,0 and 5 for x

f(-3)=(-3)^2-6(-3)+4
f(-3)=9+18+4
f(-3)=31

F(0)=(0)^2-6(0)+4

f(0)=0-0+4

f(0)=4


f(5)=(5)^2-6(5)+4

f(5)=25-30+4

f(5)=-1


Domain={-3,0,5}

Range={31,4,-1}



5 0
3 years ago
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