Answer:
Find the Roots (Zeros) f(x)=x^3-6x^2+13x-20. f(x)=x3−6x2+13x−20 f ( x ) = x 3 - 6 x 2 + 13 x - 20. Set x3−6x2+13x−20 x 3 - 6 x 2 + 13 x - 20 equal to 0 0 .
Step-by-step explanation:
hope this helps
I believe the answer is 2 :) .
Answer:
X+x =2x
Step-by-step explanation:
I think this ans may help you
Answer: a) No Solution
b) Infinite Solutions (All Real Numbers)
<u>Step-by-step explanation:</u>
4(g + 8) = 7 + 4g
4g + 32 = 7 + 4g <em>distributed 4 into g + 8</em>
32 = 7 <em> subtracted 4g from both sides</em>
Since the statement is false because 32 ≠ 7, then there is NO SOLUTION
-4(-5h - 4) = 2(10h + 8)
20h + 16 = 20h + 16 <em>distributed</em>
16 = 16 <em>subtracted 20h from both sides</em>
Since the statement is true because 16 = 16, then there are INFINITE SOLUTIONS so x can be all real numbers.
If you have a product of variables, it is not linear.
A. x(y - 5) = 2
xy - 5x = 2
xy is a product of variables, so option A is not linear.
