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fiasKO [112]
3 years ago
10

I’m confused on this one

Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0

Since ABCD is a rectangle, AB and CD are parallel sides. This means that you can set AB equal to CD to solve for x. It would be:

1/2x+6=5/2x-2.

6=4/2x-2

8=2x

4=x

So the answer would be e. 4.

Hope this helps!

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Explain how to multiply the following whole numbers 21 x 14
Lesechka [4]

Answer:

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

________

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

Step-by-step explanation:

Given

21\:\times \:14

Line up the numbers

\begin{matrix}\space\space&2&1\\ \times \:&1&4\end{matrix}

Multiply the top number by the bottom number one digit at a time starting with the ones digit left(from right to left right)

Multiply the top number by the bolded digit of the bottom number

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

Multiply the bold numbers:    1×4=4

\frac{\begin{matrix}\space\space&2&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&4\end{matrix}}

Multiply the bold numbers:    2×4=8

\frac{\begin{matrix}\space\space&\textbf{2}&1\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}

Multiply the top number by the bolded digit of the bottom number

\frac{\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}

Multiply the bold numbers:    1×1=1

\frac{\begin{matrix}\space\space&\space\space&2&\textbf{1}\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&\space\space&1&\space\space\end{matrix}}

Multiply the bold numbers:    2×1=2

\frac{\begin{matrix}\space\space&\space\space&\textbf{2}&1\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&2&1&\space\space\end{matrix}}

Add the rows to get the answer. For simplicity, fill in trailing zeros.

\frac{\begin{matrix}\space\space&\space\space&2&1\\ \space\space&\times \:&1&4\end{matrix}}{\begin{matrix}\space\space&0&8&4\\ \space\space&2&1&0\end{matrix}}

adding portion

\begin{matrix}\space\space&0&8&4\\ +&2&1&0\end{matrix}

Add the digits of the right-most column: 4+0=4

\frac{\begin{matrix}\space\space&0&8&\textbf{4}\\ +&2&1&\textbf{0}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{4}\end{matrix}}

Add the digits of the right-most column: 8+1=9

\frac{\begin{matrix}\space\space&0&\textbf{8}&4\\ +&2&\textbf{1}&0\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{9}&4\end{matrix}}

Add the digits of the right-most column: 0+2=2

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

Therefore,

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

________

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

6 0
3 years ago
What is 2a - 8a = 12 - 8a
kicyunya [14]
2a-8a=12-8a
now add 8a to both side and you get

2a= 12

divide both sides by 2 and you get

a=6
6 0
3 years ago
Read 2 more answers
For the function h(x) defined below, find function f(x) and g(x) so that h(x)=(f^ g)(x) . h(x) = ((x + 2)/x) ^ 3
dem82 [27]

Answer:

Step-by-step explanation:

c

4 0
3 years ago
SOLVE THESE 3 QUESTIONS WILL GIVE BRAINLIEST ASAP!
Fofino [41]

Answer:

A: Neither is a better deal, they cost the same person cubic foot

------

B: The large truck's volume is 2.3 times greater than the small truck's

C: At least: three vans, or two small trucks, or one large truck

Step-by-step explanation:

V=Lhw R=$/ft³

Vv=10.5(6)(6)

Vv=378 ft³

Rv=94.5/378

Rv= 25¢ per ft³

Vs=12(8)6.75

Vs=648 ft³

Rs=162/648

Rs=25¢ per ft³

------

Vl=20(8.75)8.5

Vl=1487.5 ft³

1487.5=648n

2.295=n

------

7 0
3 years ago
Who is taking in more calories if the small bag of snickers are the exact same size: A person in a group where 5 people are shar
MrRa [10]

Answer:

A person in a group where 5 people are sharing 3 small bags of snickers

Step-by-step explanation:

Let the number of calories in one bag of snickers =x

Number of calories in 3 small bags of snickers =3x

  • If 5 people share 3 small bags of snickers, 1 person's share  =\dfrac{3x}{5}

Number of calories in 2 small bags of snickers =2x

  • If 7 people share 2 small bags of snickers, 1 person's share  =\dfrac{2x}{7}

We then compare the two.

Let x=1

\dfrac{3}{5}=0.6$ calories per person\\\dfrac{2}{7}=0.29$ calories per person

Therefore, a person in a group where 5 people are sharing 3 small bags of snickers gets more calories.

3 0
3 years ago
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