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DaniilM [7]
2 years ago
13

Describe lengths of three segments that could not be used to form a triangle. Segments with lengths of 5 in., 5 in., and ______

in. Cannot form a triangle.
Mathematics
1 answer:
Vesna [10]2 years ago
8 0

Answer:

c = 11

Step-by-step explanation:

Given

Let the three sides be a, b and c

Such that:

a = b= 5

Required

Find c such that a, b and c do not form a triangle

To do this, we make use of the following triangle inequality theorem

a + b > c

a + c > b

b + c > a

To get a valid triangle, the above inequalities must be true.

To get an invalid triangle, at least one must not be true.

Substitute: a = b= 5

5 + 5 > c ===> 10 > c

5 + c > 5  ===> c > 5 - 5 ===> c > 0

5 + c > 5  ===> c > 5 - 5 ===> c > 0

The results of the inequality is: 10 > c and c > 0

Rewrite as: c > 0 and c < 10

0 < c < 10

This means that, the values of c that make a valid triangle are 1 to 9 (inclusive)

Any value outside this range, cannot form a triangle

So, we can say:

c = 11, since no options are given

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Median is ascertained by arranging a set of data in either ascending or descending order and picking the number that appears In the middle. The measure of center to use for this test is the median because it will represent the employees, it helps to arrange their income accordingly and the central item is determined.

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.Divide the sum of 13/5 and -12/7 by the product of -31/7 and -(1/2)
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2 years ago
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A woman is looking for a biker square office. She finds at office twice the area of her current office. If the perimeter of her
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Answer:

968

Step-by-step explanation:

Current office length = 22

22 * 22 = 484

484 * 2 = 968

8 0
3 years ago
Read 2 more answers
2 Here are two equations:
MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

<u>i (3,4) </u>

Putting in Equation 1:

6(3) + 4(4) = 34\\18+16=34\\34=34\\

Putting in Equation 2:

5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15

<u>ii. (4,2.5)</u>

Putting in Equation 1:

6(4) + 4(2.5) = 34\\24+10=34\\34=34\\

Putting in Equation 2:

5(4) - 2(2.5) = 15\\20-5 = 15\\15=15

<u>ill. (5,5)</u>

6(5) + 4(5) = 34\\30+20=34\\50\neq 34

Putting in Equation 2:

5(5) - 2(5) = 15\\25-10 = 15\\15=15

<u>iv. (3,2)</u>

6(3) + 4(2) = 34\\18+8=34\\26\neq 34

Putting in Equation 2:

5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

  • brainly.com/question/10534381
  • brainly.com/question/10538663

#LearnwithBrainly

8 0
3 years ago
An electronics store makes a profit of $72 for every television sold and $90 for every computer sold. The manager’s target is to
exis [7]

the complete question in the attached figure

 

we have 

$72 ------------------------------------ > for every television sold

$90 ------------------------------------ > for every computer sold.

let 

x--------------------- > numbers of television sold

y--------------------- > numbers of computer sold 

then 

72x+90y >= $360 ----------- >72x/72+90y/72 >= $360 /72---- >x+1.25y >= $5

y >= (5-x)/1.25--------------see the graph in attached figure 

 

case A---------- > (5,2) (3,3)  (1,4)

72x+90y --------- > 72*5+90*2=540 >= 360----- > is solution

72x+90y --------- > 72*3+90*3=486 >= 360----- > is solution

72x+90y --------- > 72*1+90*4=432 >= 360----- > is solution

 

case B------------ >  (4,0) (2,2)  (1,1)

72x+90y --------- > 72*4+90*0=288 < 360----- > is not solution

72x+90y --------- > 72*2+90*2=324 < 360----- > is not solution

72x+90y --------- > 72*1+90*1=162 < 360----- > is not solution

 

case C------------ >  (3,1) (2,2)  (1,0)

72x+90y --------- > 72*3+90*1=306 < 360----- > is not solution

72x+90y --------- > 72*2+90*2=324 < 360----- > is not solution

72x+90y --------- > 72*1+90*0=72 < 360----- > is not solution

 

case D------------ >  (4,0) (3,3)  (1,4)

72x+90y --------- > 72*4+90*0=288 < 360----- > is not solution

72x+90y --------- > 72*3+90*3=486 >= 360----- > is solution

72x+90y --------- > 72*1+90*4=432 >= 360----- > is solution

 

<span>the answer is case A </span>



4 0
3 years ago
Read 2 more answers
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