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3 years ago

Demonstrate that the digits of a perfect square cannot add to 2, 3, 5, 6, or 8.

1 answer:

5 0

4 cannot add to any of those numbers. Neither can 1, 9, or 16. This is because whenever the digits are added, they add up to larger numbers.

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Heyyyy hereee!! lol xhuxjzx

Irina18 [472]

Slope:5 y-intercept: -2

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3 years ago

The volume of a cylinder is 54π cubic inches and the height is 6 inches. Find the radius.

Anika [276]

Answer:

The radius of the cylinder is 3 inches.

Step-by-step explanation:

For any given cylinder, the volume can be expressed as:

volume = $\pi$ $r^{2}$ h

where r is the radius of its circular surface, and h is its height.

Given that: volume = 54π cubic inches, and the height = 6 inches.

then,

54 $\pi$ = $\pi$ x $r^{2}$ x 6

54 $\pi$ = 6 $\pi$ $r^{2}$

$r^{2}$ = $\frac{54\pi }{6\pi }$

= 9

r = $\sqrt{9}$

r = 3

The radius of the cylinder is 3 inches.

8 0

3 years ago

What does this symbol tell you to do (:) ?

Monica [59]

Answer:

That separeates the problem

Step-by-step explanation:

4 0

3 years ago

The table shows several points that lie along a line when plotted on a coordinate plane.

ladessa [460]

Answer:

no no im not sure you should know this man its ez

Step-by-step explanation:

maybe think abt it a bit more

8 0

3 years ago

Which statement describes how the graph of the given polynomial would change if the term -3x6 is adde

Lesechka [4]

Given:

Polynomial is $2x^6+9x^5-7x^3-1$ .

Term $-3x^6$ is added in the given polynomial.

To find:

The end behavior of new polynomial.

Solution:

Let, $P(x)=2x^6+9x^5-7x^3-1$ .

New polynomial is

$f(x)=2x^6+9x^5-7x^3-1+(-3x^6)$

$f(x)=(2x^6-3x^6)+9x^5-7x^3-1$

$f(x)=-x^6+9x^5-7x^3-1$

Highest power of x is 6 which is even and leading coefficient is negative. So,

$f(x)\to -\infty\text{ as }x\to -\infty$

$f(x)\to -\infty\text{ as }x\to \infty$

Both ends of the graph will approach negative infinity.

Therefore, the correct option is A.

5 0

3 years ago