Demonstrate that the digits of a perfect square cannot add to 2, 3, 5, 6, or 8.

1 answer:

5 0

4 cannot add to any of those numbers. Neither can 1, 9, or 16. This is because whenever the digits are added, they add up to larger numbers.

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DaniilM [7]

Answer:

I'm pretty positive it's (-4,-2)

Step-by-step explanation:

i looked at the grid

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2 years ago

hoa [83]

I’m pretty sure the answer is 6.125

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3 years ago

Irina-Kira [14]

If you mean the system between the two then comes (x;y)=(5;3) otherwise if solved individually they are enough to make the common denominator

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3 years ago

AysviL [449]

The answer is B. 0.30 Just add them together

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4 years ago

daser333 [38]

Y=8/2
y=4!!!!!!!!!!!!!!!!!

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3 years ago