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Studentka2010 [4]
2 years ago
9

PLZ HELP ILL MARK BRANLEIST

Mathematics
1 answer:
DaniilM [7]2 years ago
8 0

Answer:

I'm pretty positive it's (-4,-2)

Step-by-step explanation:

i looked at the grid

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How do I find range and domain in algebra (graph)​
Ierofanga [76]

Answer:

You can find the range by seeing the y-value of the plotted points.

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Hope you found this helpful!!!

4 0
3 years ago
How do you work this out? We have to make one positive and the other negative then put it on a graph correctly
ANEK [815]
The answer to Q1 along with an explanation is shown in the picture;
Having a look at all the questions, they are all essentially the same type so can all be solved similarly;
So by following the method and explanation, you should be able to do the rest of the questions.

7 0
3 years ago
Write the situation for the relationship "y = 2x - 5."
kompoz [17]
Its letter b can u please help me in my question
3 0
4 years ago
25h + 40 = −15h − 80
elena-s [515]

Answer:

<h2>h= -3</h2><h2 />

Step-by-step explanation:

25h + 40 = −15h − 80

25h + 15h = -80 - 40

40h = - 120

h = -120/4

h= -3

4 0
3 years ago
Read 2 more answers
A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coa
g100num [7]

The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

<h3><u>Solution:</u></h3>

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

8 \times h + 5 \times f = 24

8h + 5f = 24 -------- eqn 1

<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

6 \times h + 2 \times f = 16.60

6h + 2f = 16.60 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

30h + 10f = 83 -------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

<h3>h = 2.5</h3>

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

<h3>f = 0.8</h3>

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

5 0
3 years ago
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