All categories

3 years ago

Help find x. I believe it’s 13

Mathematics

1 answer:

aksik [14]3 years ago

4 0

Answer:

m∠RST = 155°

m∠RSU = 102°

Step-by-step explanation:

m∠RST = m∠RSU + m∠UST

12x - 1 = 9x - 15 + 53

12x - 9x = 1- 15 + 53

3x = 39

x = 39/3

x = 13°

m∠RST = (12x -1)° = (12 * 13 - 1)° = (156 - 1 )° = 155°

m∠RSU = (9x -15)° = (9 * 13 - 15)° = ( 117 - 15)° = 102°

You might be interested in

The utility company made a mistake on Ian’s electric bill. The company has agreed to credit Ian’s account for five transactions,

MissTica

22.50 would be the next change

8 0

3 years ago

Read 2 more answers

Sonji bought a combination lock that opens with a four-digit number created using the digits 0-9. The same digit cannot be used

Nostrana [21]

I believe the answer would be B

3 0

3 years ago

Read 2 more answers

HELP PLZZZ Write an equation For the line in standard form

Tamiku [17]

Answer:

6x -5y

Step-by-step explanation:

saw it on the picture on there

4 0

2 years ago

The arc corresponding to a central angle of 38 in a circle of radius 20 feet measures _____ feet

Anuta_ua [19.1K]

Arc length formula is s = r*theta, where s is the arc length and theta is the angle in radians (not degrees).

Here, we must convert 38 degrees to radians:

38 deg pi rad
----------- * ------------- = 0.211 pi radians = 0.663 rad
1 180 deg

Then the arc length is (20 ft)(0.663 rad) = 13.26 ft

4 0

3 years ago

Find the flux of the vector field F = 〈e-z,4z,6xy) across the curved sides of the surface S = {(x,y,z): z= cos y, lys π, 0sxs4}

Len [333]

I'll go ahead and assume you meant to say that <em>S</em> is the surface given by

$S = \left\{(x,y,z) \mid z = \cos(y)\text{ with } 0\le y\le \pi\text{ and }0\le x\le4\right\}$

This immediately gives us a parameterization for the surface,

$\vec r(x, y) = \left\langle x, y, \cos(y)\right \rangle$

The upward-pointing normal vector to this surface is then

$\vec n = \dfrac{\partial\vec r}{\partial x} \times \dfrac{\partial\vec r}{\partial y} = \left\langle0,\sin(y),1\right\rangle$

Then the flux of $\vec F(x,y,z) = \left\langle e^{-z}, 4z, 6xy\right\rangle$ across <em>S</em> is

$\displaystyle \iint_S \vec F(x,y,z)\cdot\mathrm d\vec s = \int_0^4\int_0^\pi \vec F(x,y,\cos(y))\cdot\vec n\,\mathrm dy\,\mathrm dx \\\\ = \int_0^4\int_0^\pi \left\langle e^{-\cos(y)},4\cos(y),6xy\right\rangle \cdot \left\langle0,\sin(y),1\right\rangle \,\mathrm dy\,\mathrm dx \\\\ = \int_0^4\int_0^\pi (4\sin(y)\cos(y)+6xy)\,\mathrm dy\,\mathrm dx \\\\ = 2 \int_0^4\int_0^\pi (\sin(2y) + 3xy)\,\mathrm dy\,\mathrm dx = \boxed{24\pi^2}$

8 0

3 years ago