If a translation of
t="T_{-3,-8} (x,y)" align="absmiddle" class="latex-formula"> is applied to square ABCD, what is the y-coordinate of B'?
1 answer:
The y-coordinate of B' after the translation is -6
<h3>How to determine the y-coordinate of B'?</h3>From the graph, the coordinate of B is given as:
B = (1,2)
The translation means:
(x,y) ⇒ (x - 3, y - 8)
So, we have:
B' = (1 - 3, 2 - 8)
Evaluate the difference
B' = (-2, -6)
Remove the x-coordinate
B' = -6
Hence, the y-coordinate of B' is -6
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Here are a couple I found:
<u>Similarities</u>:
- They have the same y-intercept of (0,5).
- They are both in slope-intercept form.
<u>Differences</u>:
- The line of y = -13x + 5 "falls" from left to right. The line of y = 2x + 5 "rises" from left to right.
- They have different x-intercepts. (y = 2x + 5 intersects (-
, 0) while y = -13x + 5 intersects at (
, 0)
<u></u>
<u>Explanation</u>:
Slope-intercept form is y = mx + b, and by looking at the equations, they both already fit that format, with m as their slope and b as their y-intercept. Also, since they both have a 5 as that "b," their y-intercepts are the same: (0,5).
As for differences, we can see that the coefficient in place of that "m" is positive in y = <u>2x</u> + 5 and negative in y = <u>-13x</u> + 5. Therefore, one line would rise due to their slope being positive and one would fall due to their slope being negative. They also have two different x-intercepts, which we can calculate by substituting 0 in place of the y, then isolating x.