Answer and Step-by-step explanation:
C(x) be the statement "x has a cat"
D(x) be the statement "x has a dog"
F(x) be the statement "x has a ferret".
Universe = x = all students in your class.
a) A student in your class has a cat, a dog and a ferret
= ∃x(C(x) ∧ D(x) ∧ F(x))
b) All students in your class have a cat, a dog, or a ferret = ∀x(C(x) ∨ D(x) ∨ F(x))
c) Some students in your class has a cat and a ferret but not a dog = ∃x (C(x) ∧ F(x) ∧ ¬D(x))
d) No student in this class has a cat, a dog and a ferret ¬∃x (C(x) ∧ D(x) ∧ F(x))
e) For each of the three animals, cats, dogs and ferrets, there is as student in your class who has one of the three animals. (∃xC(x)) ∧ (∃xD(x)) ∧ (∃xF(x))
Answer:
dogs = 79
dats = 90
fish = 183
Step-by-step explanation:
let the total number of dogs owned be x
no. of cats owned = x+11
no. of fish owned = x+11+x+14= 2x+25
hence,
2x+25+x+11+x=352
4x=316
x=316/4= 79mil
no. of cats owned = 79 + 11 = 90
no. of fish owned = 2(79)+25=183
-X+y is greater than or equal to 2... Multiply (1y) by 2 to get the answer for x which is 2.. and multiply (-1) by 2 to get y which is -2.. So to graph it you will put Y=-2 and X=2..
First, graph 3,-5 [RED]
then, reverse the x coordinate {3} (it is now at -3,-5) [BLUE]
next, move the point 6 to the right and 7 to the left (it is now at 3,2) [GREEN]
then, reverse the x coordinate {3}<span> (it is now at -3,2) [ORANGE]
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finally, connect the dots.
