What are the rules to solve a equation with variables on one side

Mathematics

1 answer:

amm18122 years ago

8 0

Answer:

3a-10=4+a first subtract a from 3a, this equals 2a-10=4 then add 10 to 4, this equals 2a=14, then divide 14 by 2, the answer is a=7

You might be interested in

if you know that 7 x 8=56, how can you use the commutative property of multiplication to find the product of 8 x 7 ?

Fofino [41]

Its the same thing because your just switching the order which doesn't matter when your adding or multiplying

5 0

3 years ago

Math 100 points ill give brainliest as well

Lelechka [254]

Answer:

it is the answer. let me do research and I will get answer

8 0

2 years ago

Read 2 more answers

Find the equation of a line that passes through the point (3,1) and has a gradient of -3. Leave your answer in the form y = m x

Bingel [31]

Answer:

$y = (-3)\, x + 10$ .

Step-by-step explanation:

The question requires that the equation should be in the slope-intercept form $y = m \, x + c$ . The $m$ and $c$ in this equation are constants. In particular:

$m\!$ would represent the slope of this line (also known as the gradient of this line,) whereas
$c$ would be the $y$ -intercept of this line.

The question states that the slope of this line is $(-3)$ . Therefore, $m = -3$ . Thus, the equation for this line should be in the form $y = (-3)\, x + c$ .

The value of constant $c$ could be found using the other piece of information: the point $(3,\, 1)$ is in this line. In other words, the solution $\text{$x = 3$ and $y = 1$}$ should satisfy the equation $y = (-3)\, x + c$ .