A. The lower quartile of data, which is represented by the first “whisker”
Not B or D because we don’t know the total, just where the data falls. Since we don’t know the total number of data points, we also can’t find the mean from C
(x²+4x+3)/2(x²-10x+25)
the horizontal asymptote when the numerator and the denominator have the same degree (in this case, both of a degree of 2) is ration of the coefficients of the numerator and denominator. In this case, the coefficient for numerator x² is 1, and the coefficient for the denominator 2x² is 2, so the horizontal asymptote is y=1/2=0.5
the vertical asymptote is the x value. the denominator cannot be zero, if x²-10x+25=0, x would be 5, so the vertical asymptote is x=5
this is just one example. There can be others:
(2x²+5x+2)/[(4x-7)(x-5)] for another example, but this example has a second vertical asymptote 4x-7=0 =>x=7/4
Answer:
y - 7 = 5(x + 7).
Step-by-step explanation:
The slope m (7--3)/ (-7- -9)
= 10 / 2 = 5.
y - y1 = m(x - x1)
Using the point (-7, 7):
y - 7 = 5(x + 7).
The tree is 16 feet tall.
4 x 4= 16
16 x 4= 64
Answer:
length = 10 cm; width = 25 cm
Step-by-step explanation:
Let's call the length 2x and the width 5x. Since perimeter can be calculated by multiplying the sum of the length and width by 2 we can write:
2 * (2x + 5x) = 70
2 * (7x) = 70
7x = 35
x = 5 which means the length is 2 * 5 = 10 and the width is 5 * 5 = 25.
