What is the answer to (w-6)(w+2)

Mathematics

2 answers:

Vikentia [17]3 years ago

4 0

(w - 6)(w + 2)
w^2 + 2w - 6w - 12 =
w^2 - 4w - 12 <===

Taya2010 [7]3 years ago

3 0

W^2 - 4w - 12

:) you get this answer by foiling

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Solve the initial-value problem<br><br> y' = x^4 - \frac{1}{x}y, y(1) = 1.

natta225 [31]

The ODE is linear:

$y'=x^4-\dfrac yx$

$y'+\dfrac yx=x^4$

Multiplying both sides by $x$ gives

$xy'+y=x^5$

Notice that the left side can be condensed as the derivative of a product:

$(xy)'=x^5$

Integrating both sides with respect to $x$ yields

$xy=\dfrac{x^6}6+C$

$\implies y(x)=\dfrac{x^5}6+\dfrac Cx$

Since $y(1)=1$ ,

$1=\dfrac16+C\implies C=\dfrac56$

so that

$\boxed{y(x)=\dfrac{x^5}6+\dfrac5{6x}}$

4 0

3 years ago

Problem: The mean number of bankruptcies filed per minute in the ` States in a recent year was about two. Find the probability t

tino4ka555 [31]

The number of companies is quite large. That is, n is quite large.
The probability that a company declares bankruptcy is quite small , p is quite small.
np = the mean number of bankruptcies = 2 = a finite number.
Hence we can apply Poisson distribution for the data.
P (x=5 | mean =2) = e-2 25/5! = e-2 * 32/120 = 0.036089
Alternatively
=poisson(5,2,0) = 0.036089
P(x≥ 5 | mean =2) = 1- P( x ≤ 4) = 1- e-2 (1+2+22/2!+23/3!+24/4!)= 1-e-2 (1+2+2+8/6+16/24)= 1-e-2(7)
=0.052653
Alternatively
= 1- poisson(4,2,1) =0.052653
P(X > 5 | mean =2) = 1- p(x
≤ 5) =1- e-2 (1+2+22/2!+23/3!+24/4!+25/5!)= 1-e-2(7+4/15)
=0.016564
alternatively=1-poisson(5,2,1)
=0.016564

4 0

3 years ago

Brainliest, thanks, five stars

lutik1710 [3]

Answer:

Option C) 16(0.5x - 0.75y + 2)

Step-by-step explanation:

16(0.5x - 0.75y + 2) = 16*0.5x - 0.75y*16 + 2 *16

= 8.0x - 12.0y + 32

= 8x - 12y + 32

5 0

3 years ago