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2 years ago

The length of the

1 answer:

4 0

I would estimate around 6 because say it was 6.5 and 3 then it would around the square root of like 31 and that is rounding down a lot so we would bump it up to somewhenre around 35 so the side would be around 5.8-6

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Trig identities how to prove 1- (sin^2x)/(1+cosx)= cosx

balu736 [363]

Both sides aren't equal because 1-sin^2x = cos^2x and cos^2x / 1+cosx can never equal cosx

3 0

2 years ago

Insert four arithmetic means between -1 and 14

34kurt

Answer:

Step-by-step explanation:

d = 7%2F2

-2, -2+7%2F2, -2+2%287%2F2%29, -2+3%287%2F2%29, 12

-2, -4%2F2+7%2F2, -4%2F2+14%2F2, --4%2F2+21%2F2, 12

-2, 3%2F2, 10%2F2, 17%2F2, 12

-2, 3%2F2, 5, 17%2F2, 12

5 0

2 years ago

SOMEONE, PLEASE ANSWER THIS!

IrinaVladis [17]

Answer:

Step-by-step explanation:

Solution

Start with the product

The product is 7*x where x is a number but not specified.

Now add 6

Answer: 7x + 6

This cannot be simplified any more than what it is now.

8 0

1 year ago

Read 2 more answers

How do you turn 20/10 in to a mixed fraction

Galina-37 [17]

Divide 20 by 10 you get 2 wholes with no remainder so your answer is 2

8 0

2 years ago

Please math , help

Furkat [3]

Answer:

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

Step-by-step explanation:

Mean of the batch:

The mean of the batch is the sum of all values divided by the number of items. So

$M = \frac{199+204+201+197+195+204+200}{7} = 200$

Mean in the desired interval.

Standard deviation:

Square root of the sum of the difference squared between each term and the mean, divided by the number of items. So

$S = \sqrt{\frac{(199-200)^2+(204-200)^2+(201-200)^2+(197-200)^2+(195-200)^2+(204-200)^2+(200-200)^2}{7}} = 1.18$

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

7 0

2 years ago