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3 years ago

Help find the inequalities of these problems! Plz & thank you!!

Mathematics

1 answer:

mariarad [96]3 years ago

5 0

Answer:yes imStep-by-step explanation:

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Hans wanted to find the length of the hypotenuse of the triangle. Which statement correctly identifies his error?

KonstantinChe [14]

Choice 1. He did not square 40, he just multiplied by 2.

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

The hypotenuse measures c cm while the other sides are 40 cm and 9 cm each.

Step 2:

According to the Pythagorean theorem,

$9^{2} +40^{2} = c^{2}.$

$81 + 1600 = c^{2} .$

$1681 = c^{2} .$

$\sqrt{1681} = c.$

This is the correct solution to the given problem. Hans did not square 40, he just multiplied by 2. Which is the first option.

5 0

3 years ago

What is the result when 2/5x + 1 1/4 is subtracted 2/38x - 4 1/9? (NEED ASAP)

Katyanochek1 [597]

Answer:

33 x/ 95 − 103/ 36

Step-by-step explanation: i had too many steps and i cant type them all out.

This answer is only correct if you are talking about subtracting.

7 0

3 years ago

Prove the theorem (AB )^T= B^T. A^T

Lisa [10]

Answer:

$(AB)^T = B^T.A^T (Proved)$

Step-by-step explanation:

Given (AB )^T= B^T. A^T;

To prove this expression, we need to apply multiplication law, power law and division law of indices respectively, as shown below.

$(AB)^T = B^T.A^T\\\\Start, from \ Right \ hand \ side\\\\B^T.A^T = \frac{B^T.A^T}{A^T}.\frac{B^T.A^T}{B^T} (multiply \ through) \\\\ = \frac{A^{2T}.B^{2T}}{A^T.B^T} \\\\=\frac{(AB)^{2T}}{(AB)^T} \ \ (factor \ out \ the power)\\\\= (AB)^{2T-T} \ (apply \ division \ law \ of \ indices; \ \frac{x^a}{x^b} = x^{a-b})\\\\= (AB)^T \ (Proved)$

3 0

3 years ago

What is the sum of £4(0.5) "1? n=1 O S=1.5 OS = 2 O S = 4.5 O S= 8

Lelu [443]

B. 2 …………………………,.,,,,,.,.,.,.,.,,,.,

3 0

3 years ago

If w varies inversely with the square root of t and w = 5 when t = 49,

VARVARA [1.3K]

Answer:

x=k/y

w=k/t

5=k/√49

5=k/7

k=5×7

k=35

5 0

3 years ago