I think it's c, but I can't see the whole thing.
Answer:
The answer is given below
Step-by-step explanation:
From the diagram below,Let the line AB and CD be parallel line. Let transversal line EF cut AB at Y and transversal line EF cut CD at Z.
The bisector of ∠BYZ and ∠DZY meet at O. Therefore ∠YZO = ∠DZY/2 and ∠ZYO = ∠BYZ/2
∠BYZ and ∠DZY are interior angles.
∠BYZ + ∠DZY = 180 (sum of consecutive interior angles)
∠BYZ/2 + ∠DZY/2 = 180/2
∠BYZ/2 + ∠DZY/2 = 90°
In ΔOYZ:
∠YZO + ∠ZYO + ∠YOZ = 180 (sum of angles on a straight line).
But ∠YZO = ∠DZY/2 and ∠ZYO = ∠BYZ/2
∠DZY/2 + ∠BYZ/2 + ∠YOZ = 180
90 + ∠YOZ = 180
∠YOZ = 180 - 90
∠YOZ = 90°
Therefore Angle bisectors of the same side interior angles are perpendicular.
Answer:
See the attached graph.
Step-by-step explanation:
The point-slope form of the equation for a line through point (h, k) with slope m is ...
... y -k = m(x -h)
The numbers in your given equation translate to ...
... m = 3/4, (h, k) = (-2, 3)
So, we know that one point on the line is (-2, 3). Another point on the line will be 3 units up and 4 units to the right of that. (Slope = (change in y)/(change in x) = 3/4.) Then a second point on the line will be (-2+4, 3+3) = (2, 6).