Question

A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes.

Answer 1

Complete Question

A bee flies at 9 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 13 ​minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes. What equation can you use to find the distance of the flowerbed from the hive?

Answer:

The equation is $960 = \frac{Z}{9}+ \frac{Z}{6} + 780$

Step-by-step explanation:

From the question we are told that

The velocity of the bee is $v = 9ft/s =$

The duration on the flowerbed is $t = 13 \ minutes = 780 \ s$

The velocity back to his hive is $u = 6ft / s$

The total time away from it hive is $t_t = 16 \ minutes = 960 \ s$

Now let assume the distance of the flower bed from the hive is Z

Generally the time taken for the bee to travel to the flower bed from its hive is

$t_1 = \frac{Z}{9}$

The time taken for the bee to fly back to his hive is

$t_2 = \frac{Z}{6}$

Generally the total time the bee spent outside of his house is mathematically represented as

$t_t = t_1 + t_2 + t$

=> $960 = \frac{Z}{9}+ \frac{Z}{6} + 780$