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AnnZ [28]
2 years ago
9

Tommy earned ​$ on Monday and ​$ on Tuesday. How many lucky bamboo plants can he buy with the total money he​ earned? lucky bamb

oo plants are 7$ each
Mathematics
1 answer:
Montano1993 [528]2 years ago
7 0

Answer: See explanation

Step-by-step explanation:

Your question isn't complete. But let's assume that the amount earned on Monday is $38 while $25 was earned on Tuesday.

The total amount earned for both days will be:

= $38 + $25

= $63

Since lucky bamboo plants are $7 each, we then divide the total amount gotten by $7. This will be:

= $63 / $7

= 9

Therefore, he can buy 9 lucky bamboos

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I can't figure out how to do (i + j) x (i x j)for vector calc
Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}

Then, solving the determinant

\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}

In our case,

\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}

Where we used the formula for AxB to calculate ixj.

Finally,

\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}

Thus, (i+j)x(ixj)=i-j

8 0
1 year ago
Brainly please help I been asking
IrinaVladis [17]

Answer:

114

Step-by-step explanation:

break apart the shape into 2 smaller shapes and you'll get 15 and 4 for the 1st shape multiply them and you'll get 60. Then for the second shape you'll get 6 and 9 multiply them and you'll get 54. Last add them together and you get 114. (Sorry if I get it wrong)

6 0
2 years ago
Rewrite the expression as an equivalent expression that does not contain powers of trigonometric functions greater than 1.
Gnesinka [82]
Cos^4(x) = 
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6 0
3 years ago
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attashe74 [19]

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5 0
3 years ago
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erik [133]

x*x=152


x2=152

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7 0
3 years ago
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