Answer:1124
Step-by-step explanation:
Answer:
-46 is your answer.
Step-by-step explanation:
=4-2(3+2)^2
=4-2(5)^2
=4-2(5✖️5)
=4-2(25)
Opening brackets to simplify
=4-50
=-46 is your answer.
Hope it will help you :)
Answer:
a) 10:13:3
b) 258 cm
Step-by-step explanation:
The ratio of elena's height to pavai's height is 10:13. The ratio of elena's height to kamir's height is 2:3. Their total height is 456 cm.
a) Find the ratio of elena's height to pavani's height to kamir's height in its simplest form.
10:13:3
b) What is pavani's height?
The ratio of elena's height to pavai's height is 10:13.
Their total height is 456 cm
Sum of proportions = 10 + 13 = 23
Hence:
13/23 × 456 cm
= 257.73913043 cm
Approximately = 258 cm
Answer:
D
Step-by-step explanation:
When multiplying numbers with the same base but different exponents, add the exponents together.
Answer:
<em>The SUV is running at 70 km/h</em>
Step-by-step explanation:
<u>Speed As Rate Of Change
</u>
The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.
This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:
![d=\sqrt{x^2+y^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7Bx%5E2%2By%5E2%7D)
To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:
![\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%5C%20%27%3D%5Cfrac%7Bx.x%27%2By.y%27%7D%7B%5Csqrt%7Bx%5E2%2By%5E2%7D%7D)
Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)
We'll compute :
![d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%280.8%29%5E2%2B%280.6%29%5E2%7D%3D%5Csqrt%7B0.64%2B0.36%7D)
![d=1\ km](https://tex.z-dn.net/?f=d%3D1%5C%20km)
We know d'=20 km/h, so we can solve for x' and find the speed of the SUV
![\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bx.x%27%2By.y%27%7D%7B%5Csqrt%7Bx%5E2%2By%5E2%7D%7D%3D20)
Thus we have
![x.x'+y.y'=20](https://tex.z-dn.net/?f=x.x%27%2By.y%27%3D20)
Solving for x'
![\displaystyle x'=\frac{20-y.y'}{x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%27%3D%5Cfrac%7B20-y.y%27%7D%7Bx%7D)
Since y'=-60
![\displaystyle x'=\frac{20+0.6(60)}{0.8}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%27%3D%5Cfrac%7B20%2B0.6%2860%29%7D%7B0.8%7D)
![x'=70\ km/h](https://tex.z-dn.net/?f=x%27%3D70%5C%20km%2Fh)
The SUV is running at 70 km/h