First rewrite the problem so you get
Then rewrite as
any root of 1 is one so
1/<em></em>
1/
Pull terms out from under the radical, assuming positive real numbers.
1
/2
<h2>so answer is 1/2</h2><h3>hope this helps</h3>
Answer:
Step-by-step explanation:
P1 = (2000, 1000) in the form (x1,y1)
P2 = (2012, 3400) in the form (x2,y2)
m = (y2-y1 / x2-x1)
m = ( 3400-1000 ) / (2012 - 2000)
m = 2400 / 12
m = 200
y = 200x + 800
A. Sumar 13 y 9.
22=22
B.Mover todos los términos que no contengan
d al lado derecho de la ecuación.
d=4
C.Reste 3 de −40
t−43
D.Reste 19 de 5
32=−14
A. es igual a 9.
B. 2 = es igual a 43
C. es igual a 4
D. es igual a 13
Sorry what grade are you in
F(x)=x^2+6x-2, vertex: (-3, -11)
First, put -(6)/2(1) or -b/2a.
You then get -3 as the X value of the vertex.
Next, insert -3 back into the equation to get the Y value of the vertex.
(-3)^2+6(-3)-2 = -11
You then have -11 as the Y value of the vertex.