We'll use Cramer's rule for 2 equations:
ax + by = e
cx + dy = f
5x -3y = 18 a=5 b=-3 e=18
2x + 7y = -1 c=2 d=7 f=-1
denominator determinant (dn) = (a * d) - (c * b) = 5 * 7 - (2 * -3) = 41
x = [(e * d) - (f * b)] / dn
[18 * 7 - (-1 * -3)] / 41 =
123 / 41 = 3
y = [(a * f) - (c * e)] / dn
= (5 * -1) -(2 * 18) / 41 =
-41 / 41 = -1
Source:
1728.com/cramer.htm
Answer:
9 / 64
Step-by-step explanation:
- In this task you have 2 events and you are looking for a joint probability. The first event is "Rebecca chooses a poodle". The probability of this event is:
P ( Rebecca chooses a poodle ) = 3 / 8
- because among 8 dogs there are 3 poodles.
- The second event is "Aaron selects a poodle".
This event has a probability of that is equivalent to previous selection:
P ( Aaron chooses a poodle ) = 3 / 8
- Because after Rebecca's choice the chosen poodle is replaced with the poodle; hence, there are 8 pets in total and among them there are 3 poodles.
- To calculate probability of both events ("Rebeca selects a poodle and Aaron selects a poodle") with replacement you have to multiply both calculated probabilities - condition of independent events :
P ( Aaron and Rebecca both select poodle ) = 3 / 8 * 3 / 8
= 9 / 64
Answer:
p1 = 70 deer
p2 = 98 deer
Step-by-step explanation:
We use the population growth expression:
which in our case renders:
Therefore, after 1 year the population would be:
giving a total of 70 deer
and after two years, it would be:
I think the answer c as I have estimated and this one seems like it’ll make the most sense
