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Katena32 [7]
2 years ago
5

I will mark brainliest .. help me

Mathematics
1 answer:
mrs_skeptik [129]2 years ago
7 0

Answer:

<h2><u>-2</u></h2>

Step-by-step explanation:

When I graph it and calculate the slope using both rise over run and slope formula I get -2 both times.. If you need any more explanation just ask:)  I hope I helped.

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In its monthly report, the local animal shelter states that it currently has 24 dogs and 18 cats available for adoption. Eight o
andrezito [222]

Answer with Step-by-step explanation:

We are given that

Total dogs=24

Total cats=18

Total animals=24+18=42

Male dogs=8

Male cats=6

Total male animals=8+6=14

Total female animals=42-14=28

Female cats=18-6=12

Dogs female=24-8=16

a.We have to find the probability that the pet is male, given that it is cat.

It means we have to find P(Male/cat)  

Conditional probability: P(A/B)=\frac{P(A\cap B)}{P(B)}

P(Cat)=\frac{18}{42}

P(male cat)=\frac{6}{42}

P(Male/cat)=\frac{\frac{6}{42}}{\frac{18}{42}}

P(male/cat)=\frac{6}{18}=0.33

b.P(female cat)=\frac{12}{42}

P(female)=\frac{28}{42}

P(Cat/Female)=\frac{\frac{12}{42}}{\frac{28}{42}}=\frac{12}{28}=0.43

c.P(Dog)=\frac{24}{42}

P(dog female)=\frac{16}{42}

P(female/dog)=\frac{\frac{16}{42}}{\frac{24}{42}}

P(female/dog)=\frac{16}{24}=0.67

5 0
3 years ago
Can someone please help with
Fantom [35]

The answer is B, 4000.                                        

3 0
3 years ago
An online furniture store sells chairs for $100
Sati [7]

Answer:

13 3/4

Step-by-step explanation:

8 0
3 years ago
What is the following product 3 sqrt 2(5 sqrt 6-7 sqrt 3)
Licemer1 [7]
3\sqrt2\cdot(5\sqrt6-7\sqrt3)=3\cdot5\cdot\sqrt{2\cdot6}-3\cdot7\cdot\sqrt{2\cdot3}\\\\=15\sqrt{12}-21\sqrt6=15\sqrt{4\cdot3}-21\sqrt6=15\cdot\sqrt4\cdot\sqrt3-21\sqrt6\\\\=15\cdot2\cdot\sqrt3-21\sqrt6=\boxed{30\sqrt3-21\sqrt6}
Used:\\\sqrt{a}\cdot\sqrt{b}=\sqrt{a\cdot b}

8 0
3 years ago
Read 2 more answers
The bar graph shows the number of school days Jalen had homework and did not have homework during the first six months of
Oksanka [162]

Given:

<u>In July:</u>

Number of days he has done the homework = 6

Number of days he has not done the homework = 4

<u>In August:</u>

Number of days he has done the homework = 16

Number of days he has not done the homework = 7

<u>In September:</u>

Number of days he has done the homework = 14

Number of days he has not done the homework = 4

<u>In October:</u>

Number of days he has done the homework = 14

Number of days he has not done the homework = 8

<u>In November:</u>

Number of days he has done the homework = 16

Number of days he has not done the homework = 4

<u>In December:</u>

Number of days he has done the homework = 5

Number of days he has not done the homework = 10

To find the months in which the difference between the number of days with homework and with no homework greater than 6.

Now,

<u>In July,</u>

The difference between the number of days with homework and with no homework = 6-4 = 2

<u>In August,</u>

The difference between the number of days with homework and with no homework = 16-7 = 9

<u>In September,</u>

The difference between the number of days with homework and with no homework = 14-4 = 10

<u>In October,</u>

The difference between the number of days with homework and with no homework = 14-8 = 6

<u>In November,</u>

The difference between the number of days with homework and with no homework = 16-4 = 12

<u>In December,</u>

The difference between the number of days with homework and with no homework = 10-5 = 5

Hence,

In 3 months the difference between the number of days with homework and with no homework greater than 6 and these are: August, September, November.

4 0
3 years ago
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