Answer:
1. Median = 10.1
2. A. The median represents the center.
3. D. The mode(s) can't represent the center because it (they) is(are) not a data value.
Step-by-step explanation:
Mean of a sample = sum of the samples/no of the samples
Samples in increasing order:
9.8
9.8
9.9
10.1
10.4
10.6
11.1
Mode is the sample with highest frequency.
Median is the middle entry of the data.
Mean = (9.8 + 9.8 + 9.9 + 10.1 + 10.4 + 10.6 + 11.1)/7
= 717/7
= 10.243
Median = 10.1
Mode = 9.8 because it has the highest frequency of 2
Answer: C) 50%
Step-by-step explanation:
If the polarizes are parallel, then it will be 0%. But if they're both perpendicular than it will be 50%. If they are neither parallel nor perpendicular, than it will be less than 50% and greater than 0%
Answer:
=5/21L+ -5/84
Step-by-step explanation:
=-(5/7) (-(1L/3-3/4)+1/3/4)
=(-5/7)(-(1L/3-3/4))+(-5/7)(1/3/4)
=5/21L= -15/28+ -5/84
=5/21L=+ -25/42
<h3>
Answer: 40</h3>
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Explanation:
JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.
See the diagram below.
The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)
We know that JN = 60
Let x = JQ and y = QN
The ratio of x to y is x/y and this is 2/1
x/y = 2/1
1*x = y*2
x = 2y
Now use the segment addition postulate
JQ + QN = JN
x + y = 60
2y + y = 60
3y = 60
y = 60/3
y = 20
QN = 20
JQ = 2*y = 2*QN = 2*20 = 40
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We have
JQ = 40 and QN = 20
We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.