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3 years ago

15

What is the area of the figure? 128 in2 118 in2 108 in2 48 in2

1 answer:

lys-0071 [83]3 years ago

5 0

Answer:

108 in2

Step-by-step explanation:

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HELP….ILL GIVE BRAINLIEST

Fittoniya [83]

Answer:

Step-by-step explanation:

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3 years ago

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The side of a square is 2.5 cm. Find its perimeter and area.

Neko [114]

Answer:

Perimeter = 10 cm

Area = 6.25 cm²

Step-by-step explanation:

$\bf \: Given :$

$\sf \: Side \: of \: the \: square = 2.5 \: cm$

$\bf \: To \: find:$

$\rightarrow \sf \: Perimeter$

$\sf\rightarrow Area$

$\bf \: Solution :$

$\rm \: First \: w e \: need \: to \: find \: out \: the \: perimeter \: o f \: it.$

So to find the Perimeter of the square, we'll use this formula :

$\boxed{ \sf\longrightarrow \: Perimeter = 4 \times side}$

$\bf \: Step \: 1 : \rm \: Put \: the \: value \: of \: side \: of \: the \: square :$

$\sf\longrightarrow \: Perimeter = (4 \times 2.5)cm$

$\bf \: Step\;2 : \rm Multiply :$

$\sf\longrightarrow \: Perimeter = 10 \: cm$

Hence, the perimeter would be 10 cm .

$\rule{225pt}{2pt}$

$\sf \: Now,\; let's\; find \: the \: Area .$

We know that the formula of Area to find the square is,

$\boxed{ \sf \longrightarrow \: Area = (side) {}^{2} }$

Note : The answer would always be in cm².

$\bf Step\; 1 :\rm Put\; the\; value \; of\; side \; of \; the\; square :$

$\sf\longrightarrow{Area} = (2.5) {}^{2} \: cm {}^{2}$

$\sf\longrightarrow{Area} = (2.5 × 2.5 ) \: cm {}^{2}$

$\bf \: Step\;2 : \rm Multiply :$

$\longrightarrow\sf \: Area = 6.25 \: cm {}^{2}$

Hence, the area of the square would be 6.25 cm².

<em>We are done !</em>

$\rule{225pt}{2pt}$

I hope this helps!

Let me know if you have any questions.

:D

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3 years ago

Given: measure of arc ED = 50° m∠EDK = 80° Find: ∠DSK

svetoff [14.1K]

Answer:

75°

Step-by-step explanation:

∠ESK is the supplement of ∠EDK, so is 100°. ∠ESD = 1/2·arc ED, so is 25°. Since ...

∠ESK = ∠ESD + ∠DSK

you have ...

100° = 25° + ∠DSK . . . . fill in known values

75° = ∠DSK . . . . . . . . . . subtract 25°

_____

Regarding opposite angles of an inscribed quadrilateral

Chord EK divides the 360° circle into two arc: major arc EDK and minor arc ESK. The sum of those arcs is 360°. Each of the inscribed angles that intercepts those arcs has half the measure of the arc. That is, ∠ESK intercepts arc EDK, so has half its measure. Likewise, ∠EDK intercepts arc ESK, so has half its measure. The sum of those opposite angles will be the sum of half the measures of the arcs, so half the sum of the arcs, or 1/2·360° = 180°.

This is why we can say ∠ESK is the supplement of ∠EDK.

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3 years ago

I WILL ARWARD BRAINLIEST!! PLEASE HELP!!

Ivanshal [37]

Answer:

None of the graphs of the equations pass through M(−10, 15).

Step-by-step explanation:

We are given the function $y=kx$ .

It is given that the point B lies on the graph of the given function.

1. B(2, −3)

That is, x= 2 and y= -3

So, y= kx ⇒ -3 = 2k ⇒ $k=\frac{-2}{3}$

Thus, the function is $y=\frac{-2x}{3}$

2. $B(3\frac{1}{3},-2)$ i.e. $B(\frac{10}{3},-2)$

That is, $x= \frac{10}{3}$ and y= -2

So, y= kx ⇒ $-2 = \frac{10k}{3}$ ⇒ $k=\frac{-6}{10}$ ⇒ $k=\frac{-3}{5}$

Thus, the function is $y=\frac{-3x}{5}$

From the graph plotted below, we get that,

None of the graphs of the equations pass through M(−10, 15).

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3 years ago

Question 4 Multiple Choice Worth 1 points)

babunello [35]

Answer:

What do you mean?

Step-by-step explanation:

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4 years ago

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