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padilas [110]
3 years ago
15

A boy with pneumonia has lungs with a volume of 1.9 L that fill with 0.080 mol of air when he inhales. When he exhales, his lung

volume decreases to 1.5 L. Enter the number of moles of gas that remain in his lungs after he exhales. Assume constant temperature and pressure. g
Chemistry
1 answer:
mariarad [96]3 years ago
8 0

<u>Answer:</u> The number of moles of gas remaining in the lungs is 0.063 moles

<u>Explanation:</u>

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1\text{ and }n_1 are the initial volume and number of moles

V_2\text{ and }n_2 are the final volume and number of moles

We are given:

V-1=1.9L\\n_1=0.080mol\\V_2=1.5L\\n_2=?

Putting values in above equation, we get:

\frac{1.9}{0.080}=\frac{1.5}{n_2}\\\\n_2=\frac{1.5\times 0.080}{1.9}=0.063

Hence, the number of moles of gas remaining in the lungs is 0.063 moles

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