Answer:
<h2>The answer is 615 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of seawater = 600 mL
density = 1.025 g/mL
The mass is
mass = 600 × 1.025
We have the final answer as
<h3>615 g</h3>
Hope this helps you
Answer:
O-18 is used as a tracer in many hydrologic studies. It is most often used as a component in a mixing-model and hydrograph separation, as O-18 acts conservatively and is applied naturally and uniformly over broad areas. O-18 can be used when different sources (old water/new water) have different isotopic values.
Answer:
1) 0.423 m
2) 3.107 mi
3) 68.18 kg
4) 0.0083 mem
5) 0.528 gal
6) 4300 mL
7) 32.4 mem
8) 523.013 km
9) 70.866 in
10) 2.3 yek
Note: I can’t type the about equal to sign or the sign that shows a repeating decimal, so check the image for that and my work.
Explanation:
Answer:
Three half lives.
Explanation:
Given data:
Number of half lives passed = ?
Amount of parent isotope left = 12.5%
Solution:
At time zero = 100%
At 1st half life = 100%/2 = 50%
At second half life = 50%/2 = 25%
At third half life = 25%/2 = 12.5%
It means three half lives would passed.
Answer:
TRUE!!!!
Explanation:
Water can act as both an acid and a base in solution and undergoes autoionization, where it can be both an acid and a base to itself. When mixed with an acid, water accepts hydrogen ions and acts as a base. However, when water is mixed with a base, it donates hydrogen ions and acts like an acid.
Not my words! I hope this helps :)