Answer:
²⁵⁰₉₆Cm → ²⁴⁶₉₆Cm + 4 ¹₀n
Explanation:
The complete equation is;
²⁵⁰₉₆Cm → ²⁴⁶₉₆Cm + 4 ¹₀n
- The above equation is an example of a nuclear reaction in which unstable atom of Cm emits neutrons to become more stable.
- Radioactive isotopes undergo radioactivity or decay to attain stability, they do so by emitting particles such as alpha, beta particles or a neutron.
- An atom of Cm-250 undergoes decay and emits four neutrons to form an atom of Cm-246.
1.8x10^20 atoms x (1 mole / 6.022x10^23 atoms) = 3.0x10^-4 mole
Answer:
Sulfur would gain electrons
Explanation:
Atoms want to have a complete out valence shell and because sulfur only needs 2 more electrons to complete the outer shell it would take 2 more.
Electrons cannot be located between levels except when they are in the process of moving.
The limitation of the maximum number of electrons in a given energy level can be used to account for the periodic recurrence of properties as the number of electrons increases.
Explanation:
- The Bohr's model of the atom is based on quantum mechanics.
- He suggested that electrons are contained in specific spherical orbits around the nucleus.
- The orbits are also known as shells or energy levels.
- The maximum number of electrons that can be contained by an energy level is 2n².
- An electron in an energy level has a definite amount of energy associated with it at that level.
- Electrons can undergo transitions from one level to another.
Learn more:
Bohr's mode of the atom brainly.com/question/4986277
Atomic model brainly.com/question/2965079
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Answer:
Average atomic mass of chlorine is 35.48 amu.
Explanation:
Given data:
Percent abundance of Cl-35 = 76%
Percent abundance of Cl-37 = 24%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (76×35)+(24×37) /100
Average atomic mass = 2660 + 888 / 100
Average atomic mass = 3548/ 100
Average atomic mass = 35.48 amu
Average atomic mass of chlorine is 35.48 amu.