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rusak2 [61]
3 years ago
6

Bae wya .......... please bae I can't find you please show up ​

Chemistry
2 answers:
Elan Coil [88]3 years ago
7 0

Answer:

Your babe is in your school

Explanation:

go ask babes out

ladessa [460]3 years ago
7 0
Babes and bars is probably at school bestie it’s the last day
You might be interested in
Solution A has a pH of 10, and solution B has a pH of 1. Which statement best describes these solutions?
Free_Kalibri [48]

Answer:

Solution A is a Weak Alkali, Solution B is a strong Acid.

Explanation:

At pH 10, the colour is blue, therefore it's a weak alkali.

At pH 1, the colour is red, therefore it's a strong Acid.

7 0
3 years ago
How much nano3 is needed to prepare 225 ml of a 1.55 m solution of nano3?
andrezito [222]

Answer:

= 29.64 g  NaNO3

Explanation:

Molarity is given by the formula;

Molarity = Moles/Volume in liters

Therefore;

Number of moles = Molarity × Volume in liters

                             = 1.55 M × 0.225 L

                             = 0.34875 moles NaNO3

Thus; 0.34875 moles of NaNO3 is needed equivalent to;

   = 0.34875 moles × 84.99 g/mol

   = 29.64 g

5 0
3 years ago
The process of forming two DNA molecules from one is called...
pishuonlain [190]
DNA replication? I think that would make the most sense.
4 0
3 years ago
Read 2 more answers
Use the equation
aivan3 [116]

The  number of grams  of copper  reacted is   445  grams


<u><em>calculation</em></u>

2Cu +O₂ → 2CuO

from equation above the  mole ratio  of Cu:CUO  is 2:2 =1:1, therefore the moles of Cu  is also= 7.00  moles


mass=moles   x molar mass

from periodic table  the  molar  mass of Cu= 63.5  g/mol


mass= 7.00  moles x 63.5 g/mol =445   grams

7 0
3 years ago
A voltaic cell has one half-cell with a Cu bar in a 1.00 M Cu²⁺ salt, and the other half-cell with a Cd bar in the same volume o
Anestetic [448]

The value of E°cell and ∆G is 0.74V and 133.53kJ respectively.

node reaction (oxidation reaction)

Cd ------ Cd(+2) + 2e-

Cathode reaction (reduction reaction)

Cu(+2) + 2e- -------- Cu

Redox reaction

Cu(+2) + Cd ------- Cu + Cd(2+)

E°cell = E° cathode - E° anode

E°cathode = 0.34V

E°anode = -0. 40 V

E° cell = 0.34 - (-0.40)

E°cell = 0.74V

∆G° = - n FE° cell

= -2 × 96485 × 0.74

= -142798 J

= - 142.8 kJ

∆G° = -142. 8 kJ

∆G° = R T in K

= -142. 8 = - 8.314 × 10 ^ -3 × 298 × In k

Ink = 57.64

K = 1.08 × 10 ^25

b) Cd(s) + Cu+2 (aq) ------- Cd+2 (aq) + Cu (s)

E cell = E° cell - (0. 0591 /2) log (Cd+2 /Cu+2)

= 0.74V – (0.0591/2) log(1.95/0.05)

= 0.692 V.

∆G = -n F Ecell

= -2 × 96485 × 0.692

= 133.53kJ

Thus, we found that the value of E°cell and ∆G is 0.74V and 133.53kJ respectively.

learn more about voltaic cell or electrolytic cell:

brainly.com/question/861659

#SPJ4

8 0
1 year ago
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