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Goryan [66]
3 years ago
14

Find the difference 4/9-2/17

Mathematics
2 answers:
Reil [10]3 years ago
4 0

Answer:

=  \dfrac{50}{153}   \\

Step-by-step explanation:

\frac{4}{9}  -  \frac{2}{17}  \\  \frac{4 \times 17 - 2 \times 9}{9 \times 17}  \\  =  \frac{68 - 18}{153}  \\  =  \frac{50}{153}  \\

olga55 [171]3 years ago
4 0

Answer:

50/153

Step-by-step explanation:

4/9-2/17=4*17/9*17- 2*9/17*9= (68- 18)/153= 50/153

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Graph the image of the given triangle after the transformation with the rule (x, y)→(x+3, y−5).
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Step-by-step explanation:

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Which of the following statements is TRUE about rectangle ABDC.
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WE have that a diagonal divides the rectangle into two equal triangles

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AD = hypotenuse

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From the Pythagorean theorem, we have that the square root of the square sum of the other two sides fives the hypotenuse. This mean that their sum is greater than the hypotenuse

Thus, the statement that is TRUE is AB + BD > AD. Option A

The complete question is;

Which of the following statements is TRUE about rectangle ABDC.

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d. (AB) (BD) = AD

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Step-by-step explanation:

area of figure = 5x² + 3

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3 years ago
Test-preparation organizations like Kaplan, Princeton Review, etc. often advertise their services by claiming that students gain
Umnica [9.8K]

Answer:

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Step-by-step explanation:

Previous year, the NACAC released a report concluding that exam preparation courses have minimal impact on improving SAT scores: approximately 10-20 points on average in math and 5-10 points on critical reading. The Association for college administration report also noted that this evidence is "contrary to claims made by many test preparation providers of large increases of 100 points or more on the SAT."

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7 0
3 years ago
Easy Sample Ap graphing 50pts! (Easy points!!) (ASAP) (URGENT) (Please check my other questions)​ Please
snow_lady [41]

Answer:

a)  See attachment 1.

b)  t² and D

c)  See attachment 2.

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Step-by-step explanation:

<h3><u>Part (a)</u></h3>

See attachment 1.  The line of best fit is shown in red.

<h3><u>Part (b)</u></h3>

The quantities the student should graph in order to produce a <u>linear relationship</u> between the two quantities are t² and D.

<h3><u>Part (c)</u></h3>

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\begin{array}{|l|l|l|l|l|l|}\cline{1-6} \rm t^2& 0.0196& 0.1024& 0.2116 & 0.3481& 0.3969\\\cline{1-6} \rm D & 0.10 & 0.50& 1.00 & 1.70 & 2.00\\\cline{1-6}\end{array}

<u>Plot</u> a graph of D against t² and draw a line of best fit (see attachment 2).

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\rm \implies \dfrac{1}{2}g=4.8828125...\:\rm m/s^2

\rm \implies g=2 \cdot 4.8828125...\:\rm m/s^2

\rm \implies g=9.8\:\rm m/s^2\:(1\:d.p.)

5 0
2 years ago
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