Question

Easy Sample Ap graphing 50pts! (Easy points!!) (ASAP) (URGENT) (Please check my other questions)​ Please

Answer 1

Answer:

a)  See attachment 1.

b)  t² and D

c)  See attachment 2.

d)  g = 9.8 m/s² (1 d.p.)

Step-by-step explanation:

Part (a)

See attachment 1.  The line of best fit is shown in red.

Part (b)

The quantities the student should graph in order to produce a linear relationship between the two quantities are t² and D.

Part (c)

Make a table of values of t² and D:

$\begin{array}{|l|l|l|l|l|l|}\cline{1-6} \rm t^2& 0.0196& 0.1024& 0.2116 & 0.3481& 0.3969\\\cline{1-6} \rm D & 0.10 & 0.50& 1.00 & 1.70 & 2.00\\\cline{1-6}\end{array}$

Plot a graph of D against t² and draw a line of best fit (see attachment 2).

Part (d)

From inspection of the graph, the line of best fit passes through the origin (0, 0) and (0.1024, 5.0).  Therefore, use these two points to find the slope of the line:

$\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0.5-0}{0.1024-0}=4.8828125...\:\rm m/s^2$

Therefore:

$\rm \implies \dfrac{1}{2}g=4.8828125...\:\rm m/s^2$

$\rm \implies g=2 \cdot 4.8828125...\:\rm m/s^2$

$\rm \implies g=9.8\:\rm m/s^2\:(1\:d.p.)$