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Marina86 [1]
2 years ago
9

Harvey is working on a weekly budget. He earns $459 per week. Harvey spends $200 per week on rent and utilities plus $85 per wee

k on food. After paying for rent, utilities, and food, Harvey deposits 2/3 of the amount left over into a savings account. He can spend the rest of the money on entertainment.
How much money does Harvey have to spend on entertainment per week?
Mathematics
2 answers:
Sedaia [141]2 years ago
8 0

Answer:

$197

Step-by-step explanation:

459-200-85+23

Leona [35]2 years ago
7 0

Answer: Harvey has $174 per week to spend on entertainment.

Step-by-step explanation: first Add the money he has throughout the week which is $200 + 85 =285 and just subtract $459 and 285.

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Algebra 2 need a lil help
babymother [125]

Answer:

1

Step-by-step explanation:

The zeroes or x intercepts are when the line crosses through the x-axis.

In this case you should only have one being (1) because the line only passes the x-axis once. Also by real zeroes it means non -5i #s so nothing with an (i) for imaginary #'s.

Hope this helps.

8 0
2 years ago
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True or false: Exterior angles are the angles created when the sides of the triangle are shortened.(1 point)
Lady_Fox [76]

Answer:

This statement is false. Exterior angles are the angles created when the sides of the triangle are extended.

Step-by-step explanation:

Exterior angles are the angle between the any reference side and line extended from the adjacent side.

the sum of exterior and interior angle is 180 as it lies on a straight line.

_______________________________________________

based on above definition the given statement becomes false.

Hence, correct choice is option third

This statement is false. Exterior angles are the angles created when the sides of the triangle are extended.

5 0
3 years ago
Use the quadratic model P(x)=25^2-24x+615 if x equals 8
Lynna [10]
P(x) = 25^2 -24x + 615
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8 0
2 years ago
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Find the solution for this inequality<br> -3x + 5 &lt; 5
n200080 [17]

Answer:

2

Step-by-step explanation:

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6 0
3 years ago
Assume that military aircraft use ejection seats designed for men weighing between 141.8 lb and 218 lb. If​ women's weights are
Mariulka [41]

Answer:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(173.6,49.8)  

Where \mu=173.6 and \sigma=49.8

We are interested on this probability

P(141.8

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

8 0
2 years ago
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