A polynomial function has a root of –3 with multiplicity 2, a root of 0 with multiplicity 1, a root of 1 with multiplicity 1, an
d a root of 3 with multiplicity 2. If the function has a positive leading coefficient and is of even degree, which could be the graph of the function?
2 answers:
We are given a polynomial function has :
A root of –3 (multiplicity 2).
Therefore, one factor would be (x+3)^2
A root of 0 with multiplicity 1.
Therefore another factor is x.
A root of 1 with multiplicity 1.
Therefore another factor is (x-1).
A root of 3 with multiplicity 2.
Therefore, another factor would be (x-3)^2
Therefore, polynomial function would
So, the graph of the function would look like as attachment:
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Answer:
Step-by-step explanation:
The slope of a graph is also known as its gradient, which is the steepness of the graph.
If we are given two points on the line, we can find the slope by taking rise/ run, which is the ratio of the change in y-coordinate against the change in the x-coordinate. This can also be written as a formula:
☆ (x₁, y₁) is the first coordinate and (x₂, y₂) is the second coordinate
In this question, we are given the equation of the line. This equation is already in the slope-intercept form (y= mx +c) since the coefficient of y is 1 and all the other terms are on the other side of the equal sign. In the slope-intercept form, m is the slope while c is the y-intercept.
m= ⅘ since the coefficient of x is ⅘ in the given equation (when the equation is in the slope-intercept form).