Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
The number of tissues that can fit the container will be given by:
[volume of the container]/[volume of tissue box]
volume of container:
V=length×width×height
V=19.5×39×19.5
V=14829.75
Volume of tissue box:
v=6.5×6.5×6.5
v=274.625
Number of tissues in the container:
14829.75/274.625
=54
Answer: 54 tissue paper boxes
Answer:
B. (b+3c)+(b+3c)
C. 2(b)+2(3c)
Step-by-step explanation:
we have
Distribute the number 2
Verify each case
case A) 3(b+2c)
distribute the number 3
therefore
Choice A is not equivalent to the given expression
case B) (b+3c)+(b+3c)
Combine like terms
therefore
Choice B is equivalent to the given expression
case C) 2(b)+2(3c)
Multiply both terns by 2
therefore
Choice C is equivalent to the given expression
Step-by-step explanation:
3/8 and 11/15
LCM = 30
3/8x4 and 11/15x2
12/30 and 22/30
22/30-12/30
=10/30
The difference is 10/30
The larger sum is 11/15
vous êtes les bienvenus, baisers!
If D is the midpoint of CE, then CD must be equal to DE
Answer: C
