6/10 is greater of course. Hope this helps!
Answer:
The rate of study is 5 items per hour.
Step-by-step explanation:
Number of items a person can learn after t hours of instruction, w(t) is given by:
![w(t)=15\sqrt[3]{t^{2}}](https://tex.z-dn.net/?f=w%28t%29%3D15%5Csqrt%5B3%5D%7Bt%5E%7B2%7D%7D)
We want to determine the rate of learning at any time t. The rate is the derivative of w(t) with respect to time.
![\frac{dw(t)}{dt} =\frac{d}{dt} 15\sqrt[3]{t^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7Bdw%28t%29%7D%7Bdt%7D%20%3D%5Cfrac%7Bd%7D%7Bdt%7D%2015%5Csqrt%5B3%5D%7Bt%5E%7B2%7D%7D)



Therefore, the rate of learning at any time t

At the end of 8 hours, t=8

=5
The rate of study is 5 items per hour.
Answer:
1. slanting upward because the slope is positive one.
2. A: 3/4 B: 4/-3
3. A: 3 B: y=3x-10
Step-by-step explanation:
1. (-2-7)/(-4-5) = -9/-9 = 1
2. A: (7-4)/(7-3) = 3/4
B: (8-0)/(-6-0) = 8/-6 = 4/-3
3. find the slope first so (4-1)/(2-1)= 3/1. then you plug in point C to find the y intercept so y=mx+b would be 2=3(4)+b which makes it so b is -10. the new equation would be y=3x-10
Answer:
The number of days are independent and the total number of minutes are dependent.
The required model for the situation is 
The table is shown below:
Step-by-step explanation:
Consider the provided information.
Joshua spends 25 minutes of each day reading. Let d be the number of days that he reads, and let m represent the total minutes of reading.
We need to determine which variable is independent and which is dependent.
Here, the number of days are independent and the total number of minutes are dependent.
If he spends 25 minutes each day. So the total number of minutes in d days are:

The required model for the situation is 
Now make the table which showing the number of minutes spent reading over 7 days.
Substitute the value of d from 1 to 7 in 
Number of days(D) Minutes(M)
1 25
2 50
3 75
4 100
5 125
6 150
7 175
Looks good to me. Calculation is correct. Although you might want to add to #1 your description; that the width of the rectangle is the circumference of the circle (w = 2πr) and that you add the surfaces together to get the total surface area.
total surface area = area of rectangular part + area of circular parts
SA = 2πrL + 2πr²