Hmm let's say
c = commercial launches
n = non-commercial launches
we know the total of launches were 53 for that year, so
c + n = 53
we also know that, whatever "c" is, "n" is "<span>was one more than three times" that
so... three times "c", 3 * c or 3c
one more than that?
3c + 1
so.. whatever "c" is, n = 3c + 1
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![\bf \begin{cases} c+n=53 \\\\ \boxed{n}=3c+1\\ --------------\\ c+n=53\implies c+\boxed{3c+1}=53 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Ac%2Bn%3D53%0A%5C%5C%5C%5C%0A%5Cboxed%7Bn%7D%3D3c%2B1%5C%5C%0A--------------%5C%5C%0Ac%2Bn%3D53%5Cimplies%20c%2B%5Cboxed%7B3c%2B1%7D%3D53%0A%5Cend%7Bcases%7D)
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solve for "c", to see how many commercial launches were there
what about "n"? well, n = 3c + 1</span>
The third angle should be 83.
90+7+83=180
Answer:
the ratio is the same
Step-by-step explanation:
Girls
12 out of 30
12/30
Divide top and bottom by 6
2/5
Boys
16 out of 40
16/40
Divide top and bottom by 8
2/5