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2 years ago

What is the benchmark decimal for 0.0034?

Mathematics

1 answer:

lbvjy [14]2 years ago

3 0

Answer:

34%

Step-by-step explanation:

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Determine the x- and y-

rjkz [21]

Answer and working out attached, hope this helps

3 0

2 years ago

roshaun and lea go to an amusement park. lea spends 1/2 of her money, and roshaun spends 1/4 of his money. is it possible for ro

Olin [163]

Yes it is possible for Roshaun to spend more money than Lea because he could have had more money than her to start with making his fraction larger than hers.

3 0

3 years ago

Domain and range of the function and it’s inverse

sineoko [7]

Answer:

B (second table in list)

Step-by-step explanation:

The function is a quadratic with vertex and y-intercept at (0,-2). The parabola opens up meaning only y - values above -2 are a part of the function. Since range is the set of all y values, then the range is $y\geq -2$ .

The domain is not restricted and it is all real numbers.

The inverse of the function is where x and y are switched. So the range becomes the domain and vice verse.

This means the domain of the inverse is $x\geq -2$ and the range of the inverse is all real numbers.

8 0

3 years ago

If correct I will give brainly

Marizza181 [45]

Answer:

Step-by-step explanation:

all you need to do is switch the x with 12

5 0

3 years ago

HELPP!!

SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

7 0

3 years ago