<span>1. Solve the system by substitution -2x+y=-11, 3x-4y=11.
</span>-2x+y=-11<span>
y = 2x-11
</span><span>3x-4y=11
</span>3x-4(2x-11)=11
3x -8x + 44 = 11
-5x = -33
<span>x =33/5
y = 11/5
</span><span>2. Solve the system using elimination- 2x+6y=-12, 5x-5y=10.
</span><span>(-2x+6y=-12)5
</span>-10x + 30y = -60
<span>(5x-5y=10)2
</span>10x - 10y = 20
Adding the two equations,
<span>-10x + 30y = -60
</span><span>10x - 10y = 20
</span>
20y = -40
y = -2
x = 0
<span>3. What is the solution of the following system?-3x-2y=-12, 9x+6y=-9.
</span><span>-3x-2y=-12
</span>y = -3/2 x + 6
<span>9x+6y=-9
</span>y = -3/2 x - 3/2
Since the slopes are equal then they are parallel lines so they never meet at one point.
Let
x--------------> the complete figure
we know that
the figure is divided into 6 equal parts
x= (x/6)+(x/6)+(x/6)+(x/6)+(x/6)+(x/6)
red=(x/6)+(x/6)--------> red=(2x/6)=x/3
blue=(x/6)+(x/6)+(x/6)+(x/6)=(4x/6)=2x/3
Rashad say that 2/4 of the figure is red-------> Rashad is wrong
because (2/4) <span>It is half of the figure
</span>the correct thing is to say (1/3) o the figure is red and (2/3) of the figure is blue
Answer would be 7.33 Since the last digit 5 is rounded up
Answer:
Graph 1: 2/9, 2: 1/2 3: 1/5
Step-by-step explanation:
To find slope you do y2-y1/x2-x1 (rise over run). For graph 1, y2=2, y1=0. x2=9,x1=0. 2-0=2, 9-0=0, so the overall slope is 2/9
