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natali 33 [55]
3 years ago
15

The area of two rectangles is given by he functions: area of a rectangle A:f(x)= 4x2+6x area of rectangle B:g(x)=3x2-x Which fun

ction represents the difference? A.h(x)=7x2-5x B.h(x)=x2-7x C.h(x)=x2+5x D.h(x)=x2+7x
Mathematics
2 answers:
dusya [7]3 years ago
7 0

Answer:

x^2+7x if you are asked to find the difference of a function f and function g

Step-by-step explanation:

We are asked to A-B or f(x)-g(x).

(4x^2+6x)-(3x^2-x)

4x^2+6x-3x^2+x

The like terms I'm going to pair up.

4x^2-3x^2+6x+x

1x^2          +7x

x^2            +7x

The answer is x^2+7x

Angelina_Jolie [31]3 years ago
4 0

Answer:

OPTION D: h(x)=x^2+7x

Step-by-step explanation:

You know that the area of Rectangle A is given by :

f(x)= 4x^2+6x

And the area of Rectangle B is given by:

g(x)=3x^2-x

Therefore, in otder to find the function that represents the difference, you need to subtract the functions f(x) and g(x).

Then, you get this function h(x):

 h(x)=f(x)-g(x)\\\\h(x)= (4x^2+6x)-(3x^2-x)\\\\h(x)=4x^2+6x-3x^2+x\\\\h(x)=x^2+7x

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Find the area of the isosceles triangle. please help thanks
fiasKO [112]

Answer:

1080 m^2 Don't submit m^2 in your answer.

Step-by-step explanation:

Givens

The catch is to find h

To do that, use a^2 + b^2 = c^2

a b and c are in the same 1/2 triangle.

a = 48/2 = 24 m

b = h = ?

c = 51 meters

Solution

a^2 + b^2 = 51^2                      Substitute for b^2 = h^2

24^2 + h^2 = 51^2                   Expand 24^2 and 51^2

576 + h^2 = 2601                    Subtract 576 from both sides

h^2 = 2601 - 576

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h = 45

Area

Area = 1/2 b * h

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Notice that to find h you only use 1/2 of 48 because that is the base of the right triangle.

To find the area, you need to use all of 48 because 48 is the full length of the base.

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