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DaniilM [7]
3 years ago
11

3x + 4> 10 please show working ​

Mathematics
1 answer:
deff fn [24]3 years ago
4 0

Answer:

Step-by-step explanation:

3x + 4 > 10

3x > 10 - 4

3x > 6

x > 6/3

x > 2

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Unit 8 right triangles and trigonometry homework 3 similar right triangles and geometric mean
Ugo [173]

The right triangles that have an altitude which forms two right triangles

are similar to the two right triangles formed.

Responses:

1. ΔLJK ~ ΔKJM

ΔLJK ~ ΔLKM

ΔKJM ~ ΔLKM

2. ΔYWZ ~ ΔZWX

ΔYWZ ~ ΔYZW

ΔZWX ~ ΔYZW

3. x = <u>4.8</u>

4. x ≈ <u>14.48</u>

5. x ≈ <u>11.37</u>

6. G.M. = <u>12·√3</u>

7. G.M. = <u>6·√5</u>

<u />

<h3>What condition guarantees the similarity of the right triangles?</h3>

1. ∠LMK = 90° given

∠JMK + ∠LMK  = 180° linear pair angles

∠JMK = 180° - 90° = 90°

∠JKL ≅ ∠JMK All 90° angles are congruent

∠LJK ≅ ∠LJK reflexive property

  • <u>ΔLJK is similar to ΔKJM</u> by Angle–Angle, AA, similarity postulate

∠JLK ≅ ∠JLK by reflexive property

  • <u>ΔLJK is similar to ΔLKM</u> by AA similarity

By the property of equality for triangles that have equal interior angles, we have;

  • <u>ΔKJM ~ ΔLKM</u>

2. ∠YWZ ≅ ∠YWZ by reflexive property

∠WXZ ≅ ∠YZW all 90° angle are congruent

  • <u>ΔYWZ is similar to ΔZWX</u>, by AA similarity postulate

∠XYZ ≅ ∠WYZ by reflexive property

∠YXZ ≅ ∠YZW all 90° are congruent

  • <u>ΔYWZ is similar to ΔYZW</u> by AA similarity postulate

Therefore;

  • <u>ΔZWX ~ ΔYZW</u>

3. The ratio of corresponding sides in similar triangles are equal

From the similar triangles, we have;

\dfrac{8}{10} = \mathbf{ \dfrac{x}{6}}

8 × 6 = 10 × x

48 = 10·x

  • x = \dfrac{48}{10} = \underline{4.8}

3. From the similar triangles, we have;

\mathbf{\dfrac{20}{29}} = \dfrac{x}{21}

20 × 21 = x × 29

420 = 29·x

  • x = \dfrac{420}{29 } \approx \underline{14.48}

4. From the similar triangles, we have;

\mathbf{\dfrac{20}{52}} = \dfrac{x}{48}

20 × 48 = 52 × x

  • x = \dfrac{20 \times 48}{52}  = \dfrac{240}{13}  \approx \underline{18.46}

5. From the similar triangles, we have;

\mathbf{\dfrac{13.2}{26}} = \dfrac{x}{22.4}

13.2 × 22.4 = 26 × x

  • x = \dfrac{13.2 \times 22.4}{26} \approx \underline{ 11.37}

6. The geometric mean, G.M. is given by the formula;

G.M. = \mathbf{\sqrt[n]{x_1 \times x_2 \times x_3  ... x_n}}

The geometric mean of 16 and 27 is therefore;

  • G.M. = \sqrt[2]{16 \times 27}  = \sqrt[2]{432} = \sqrt[2]{144 \times 3} = \mathbf{12 \cdot \sqrt{3}}

  • The geometric mean of 16 and 27 is <u>12·√3</u>

<u />

7. The geometric mean of 5 and 36 is found as follows;

G.M. = \sqrt[2]{5 \times 36}  = \sqrt[2]{180} = \sqrt[2]{36 \times 5} = \mathbf{ 6 \cdot \sqrt{5}}

  • The geometric mean of 5 and 36 is <u>6·√5</u>

Learn more about the AA similarity postulate and geometric mean here:

brainly.com/question/12002948

brainly.com/question/12457640

7 0
3 years ago
Solve both questions please ❤️❤️
harina [27]

Answer:

1. y=7.2

2. x=18

Step-by-step explanation:

1. Triangles CMN and CBA are similar triangles (by AAA postulate). Similar triangles have proportional corresponding sides, so

\dfrac{CM}{CB}=\dfrac{CN}{CA}\\ \\\dfrac{12}{12+y}=\dfrac{10}{10+6}\\ \\12\cdot 16=10\cdot (12+y)\\ \\192=120+10y\\ \\10y=72\\ \\y=7.2

2. GK is angle G bisector. Use angle bisector's property:

\dfrac{GH}{GI}=\dfrac{KH}{KI}\\ \\\dfrac{40}{24}=\dfrac{30}{x}\\ \\40x=24\cdot 30\\ \\4x=24\cdot 3\\ \\x=6\cdot 3=18

8 0
3 years ago
With sales tax, it costs $29.58 to buy a $29 volleyball net. What is the sales tax percentage?
zubka84 [21]
2% is the correct answer...
4 0
4 years ago
Read 2 more answers
Eve has 24 stamps each valued at $24.75.what is the total value of her stamps?
Dafna11 [192]
Simple multiplication..
24 * 24.75 = $ 594.00 <== their total value
6 0
3 years ago
Read 2 more answers
Solve the quadratic equation by completing the square.x ^ 2 + 16x + 59 = 0First, choose the appropriate form and fill in the bla
nikitadnepr [17]

Given:

There are given the quadratic equation:

x^2+16x+59=0

Explanation:

To find the value of x by using completing the square, first, we need to subtract 59 on both sides of the given equation:

So,

From the given equation:

\begin{gathered} x^2+16x+59=0 \\ x^2+16x+59-59=0-59 \\ x^2+16x=-59 \end{gathered}

Now,

Take half of the x term and square it:

So,

From the x term,

\lbrack16\cdot\frac{1}{2}\rbrack^2=64

Then,

Add 64 on both sides of the above equation.

So,

\begin{gathered} x^2+16x=-59 \\ x^2+16x+64=-59+64 \\ x^2+16x+64=5 \\ (x+8)^2=5 \end{gathered}

Hence, an option first is correct:

(x+8)^2=5

Now,

From the above square:

\begin{gathered} (x+8)^2=5 \\ x+8=\pm\sqrt[]{5} \end{gathered}

Then,

Subtract 8 from both sides of the equation;;

So,

\begin{gathered} x+8=\pm\sqrt[]{5} \\ x+8-8=\pm\sqrt[]{5}-8 \\ x=\pm\sqrt[]{5}-8 \\ x=\sqrt[]{5}-8,\pm\sqrt[]{5}-8 \\ x=-5.7639,-10.236067 \end{gathered}

Final answer:

Hence, the value of x is shown below:

x=(-5.76,-10.24)

4 0
1 year ago
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