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3 years ago

Find the value of x if A, B, and C are collinear points and B is between A and C.

1 answer:

4 0

By segment addition rule AB + BC = AC
3x + 2x - 7 = 2x + 35
3x = 42
x = 1 4
CHECK
3(14) = 42
2(14)-7= 21
-------------------
2(14)+ 35= 63

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Combine like terms. 5/6x - 2/3x A. 1/6x B. 1/3x C. 1/2x D. x

professor190 [17]

The answer would be A
$\frac{5}{6} - \frac{2}{3} or \frac{4}{6} = \frac{1}{6}$

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4 years ago

there are 16 sixth graders and 20 seventh graders in the robotics club. Wants to organize the club members into equal size each

lina2011 [118]

the answer is 4 because 16 and 20 can both be divided by 4.

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3 years ago

Two sets of equatic expressions are shown below in various forms: Line 1: x2 + 3x + 2 (x + 1)(x + 2) (x + 1.5)2 − 0.25 Line 2: x

kherson [118]

Answer: The correct line is

$\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.$

Step-by-step explanation: We are given the following two sets of quadratic expressions in various forms:

$\textup{Line 1: }x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25,\\\\\textup{Line 2 :}x^2+5x+6=(x+2)(x+3)=(x+2.5)^2+6.25.$

We are to select one of the lines from above that represent three equivalent expressions.

We can see that there are three different forms of a quadratic expression in each of the lines:

First one is the simplified form, second is the factorised form and third one is the vertex form.

So, to check which line is correct, we need to calculate the factorised form and the vertex form from the simplified form.

We have

$\textup{Line 1: }\\\\x^2+3x+2\\\\=x^2+2x+x+2\\\\=x(x+2)+1(x+2)\\\\=(x+1)(x+2),$

and

$x^2+3x+2\\\\=x^2+2\times x\times 1.5+(1.5)^2-(1.5)^2+2\\\\=(x+1.5)^2-2.25+2\\\\=(x+1.5)^2-0.25.$

So,

$\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.$

Thus, Line 1 contains three equivalent expressions.

Now,

$\textup{Line 2: }\\\\x^2+5x+6\\\\=x^2+3x+2x+6\\\\=x(x+3)+2(x+3)\\\\=(x+2)(x+3),$

and

$x^2+5x+6\\\\=x^2+2\times x\times 2.5+(2.5)^2-(2.5)^2+6\\\\=(x+2.5)^2-6.25+6\\\\=(x+2.5)^2-0.25\neq (x+2.5)^2+6.25.$

So,

$\textup{Line 2 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2+6.25.$

Thus, Line 2 does not contain three equivalent expressions.

Hence, Line 1 is correct.

7 0

3 years ago

8x - 5 - 6 - 7 <br> Can someone solve this

Iteru [2.4K]

Answer:

8x-18

Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

Help me please!!

Setler [38]

Answer:

3.A

2.59 %

3.B

.16 x 2,000 = 320

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3 years ago