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shutvik [7]
3 years ago
13

1) What is 0.627 written in expanded form using decimals?

Mathematics
2 answers:
Lilit [14]3 years ago
7 0
So in order it goes from: 0.6, 0.02, 0.007
ale4655 [162]3 years ago
5 0

Answer:

(6x 0.1)+(2x 0.01)+(7x 0.001)

Step-by-step explanation:

You multiply

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Which of the following is an arithmetic sequence
PolarNik [594]

Answer:

D

Step-by-step explanation:

they all add up by 3

4 0
4 years ago
Read 2 more answers
Whats 3/5 + -7/5<br>A.) -2<br>B.)-4/5<br>C.)4/5<br>D.)2
Sav [38]

\text{Denominators are the same, therefore:}\\\\\dfrac{3}{5}+\dfrac{-7}{5}=\dfrac{3+(-7)}{5}=\dfrac{3-7}{5}=\dfrac{-4}{5}



Answer: B.) -4/5

4 0
4 years ago
Solve: 20/x = 2<br><br> a.<br> x = 40<br> b.<br> x = 10<br> c. <br> x = 20<br> d.<br> x = 15
andre [41]

<u><em>Answer: the answer is 10! B)X=10 </em></u>

8 0
3 years ago
Given ΔADC and ΔAEB, What is AE?
chubhunter [2.5K]

Answer:

AE = 43.2 units

Step-by-step explanation:

As per the given question image, it can be seen that in the \triangle ADC \text { and }\triangle AEB :

1. \angle B = \angle C = 90^\circ

2. \angle A is common to both the triangles.

3. Two angles are common, so the third angle \angle E is also equal to \angle D.

All the three angles in the \triangle ADC \text { and }\triangle AEB are equal to each other, hence the triangles are similar.

As per the property of similar triangles, the ratio of their sides will be equal.

AB : AC = AE : AD

AC = 88 units

BC = 55 units

AB = AC - AB = 33 units

Let side AE = x units

Side AD = AE + ED

So, AD = x + 72

Using the ratio:

\dfrac{AB}{AC} = \dfrac{AE}{AD}\\\Rightarrow \dfrac{33}{55} = \dfrac{x}{x+72}\\\Rightarrow 55x = 33 \times 72\\\Rightarrow x = \dfrac{3\times 72}{5}\\\Rightarrow x = 43.2\ units

So, AE = 43.2 units

4 0
3 years ago
Choose the correct equation for the parabola based on the given information. Given: Focus:(2,8) Directrix: y = 4 a. 2(y-2)= (x-
Harman [31]
<h3>Answer:  c. 8(y-6) = (x-2)^2</h3>

Explanation:

The directrix is horizontal, so the axis of symmetry is vertical. We'll have an x^2 term. The vertical distance from y = 4 to y = 8 is 4 units. Cut this in half to get 2, which is the focal distance p = 2.

The point (2,4) is directly below (2,8), and the point is on the directrix. The midpoint between (2,4) and (2,8) is (2,6). This is the vertex.

(h,k) = (2,6)

4p(y-k) = (x-h)^2

4*2(y-6) = (x-2)^2

8(y-6) = (x-2)^2

8 0
4 years ago
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