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gulaghasi [49]
2 years ago
15

There are 1,000 cans of cat food produced daily at a factory. in the meeting last week, the

Mathematics
1 answer:
BaLLatris [955]2 years ago
4 0

Using the binomial distribution, it is found that the true statement related to the number of cans of cat food the company expects to be dented is given by:

B. The factory can expect to have an average of 50 cans dented in a day.

<h3>What is the binomial probability distribution?</h3>

It is the probability of exactly<u> x successes on n repeated trials, with p probability</u> of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

In this problem, we have that there are 1000 cans, each with a probability of 1/20 of being dented, hence:

n = 1000, p = 1/20 = 0.05.

The expected value is then given by:

E(X) = np = 1000 x 0.05 = 50.

Researching the problem on the internet, the correct option is given by:

B. The factory can expect to have an average of 50 cans dented in a day.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

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The simple interest on a certain sum of money for 2 years at 5% per annum is Rs 320. What will be the compound interest on the s
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Answer:

Rs 328

Step-by-step explanation:

Find the <u>principal</u> amount invested.

<u>Simple Interest Formula</u>

I = Prt

where:

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  • r = interest rate (in decimal form)
  • t = time (in years)

Given:

  • I = Rs 320
  • r = 5% = 0.05
  • t = 2 years

Substitute the given values into the formula and solve for P:

⇒ 320 = P(0.05)(2)

⇒ 320 = P(0.1)

⇒ P = 3200

<u>Compound Interest Formula</u>

\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}

where:

  • I = interest earned
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = 3200
  • r = 5% = 0.05
  • n = 1 (annually)
  • t = 2 years

Substitute the given values into the formula and solve for I:

\implies \sf I=3200\left(1+\frac{0.05}{1}\right)^{2} -3200

\implies \sf I=3200\left(1.05\right)^{2} -3200

\implies \sf I=3200\left(1.1025\right) -3200

\implies \sf I=3528-3200

\implies \sf I=328

Therefore, the compound interest on the same sum for the same time at the same rate is Rs 328.

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