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Alexxx [7]
2 years ago
14

In a positive correlation, __________.

Mathematics
1 answer:
Brut [27]2 years ago
7 0
Im pretty sure its b
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WILL GIVE BRAINLIEST!!!
meriva

Answer:

It is: (f(2) - f(0))/(2 - 0)

f(2) = 250(0.5)(2) = 250

f(0) = 250 (0.5)(0) = 0

So: (250 - 0)/(2 - 0) = 250/2 = 175

The average rate of change is 175.

Step-by-step explanation:

7 0
2 years ago
Zack, teri, and paco combined the foreign stamps from their collections for a stamp show. out of their collections. 3/10 of zack
babymother [125]
The complete question in the attached figure

Let 
Z---------------- > number of zacks stamps collections  <span>for a stamp show
</span>T---------------- > number of teri's stamps collections  <span>for a stamp show
</span>P--------------- > number of pacos  stamps collections  for a stamp show
we know that
Z=(3/10)*30-----------> Z=9
T=(5/6)*18------------ > T=15
P=(3/8)*24------------->P=9

the answer is
number of zacks stamps collections  for a stamp show was 9
number of teri's stamps collections  for a stamp show was 15
number of pacos  stamps collections <span>for a stamp show </span>was 9
In their display were 33 stamps



4 0
3 years ago
Read 2 more answers
Which is the correct classification of sqrt 32
labwork [276]

Answer:

irrational number, nonrepeating decimal

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Express in the form n : 1 12 : 2
Thepotemich [5.8K]

Answer:

6 : 1

Step-by-step explanation:

Given the ratio

12 : 2 ( divide both parts by 2 )

= 6 : 1 ← in the form n : 1

4 0
2 years ago
Consider a binomial distribution of 200 trials with expected value 80 and standard deviation of about 6.9. Use the criterion tha
mote1985 [20]

Answer:

The correct answer is option 'a' : 120 is more than 2.5 standard deviations above the expected value.

Step-by-step explanation:

For an exponential distribution we have

The expected value μ = 80

No of trails n = 200

Thus we have

p=\frac{80}{200}=0.4

The deviation is related to expected value and probability as

\sigma =\sqrt{np(1-p)}\\\\\therefore \sigma =\sqrt{200\cdot 0.4\cdot (1-0.4)}=6.9

Thus the values between the given deviation is

x_{1}=80-2.5\times 6.9=62.75\\\\x_{2}=80+6.9\times 2.5=97.25

Now since 120 successes are out of the range of [62.75,97.25] thus 120 is more than the expected value.

5 0
3 years ago
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