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To know the answer, we determine the polarities of the solvent we have. Water is polar and gasoline is nonpolar. We remember that like dissolves like. Therefore, the answers are:
<span>table sugar = water
motor oil = gasoline
rubber from tire marks = gasoline
adhesive residue from a packing tape = gasoline</span>
Answer:
The final temperature of the water mixture is 47.85°C
Explanation :
Given,
For Warm Water
mass = 10grams
Temperature = 105°C
For Cold Water
mass = 25grams
Temperature = 25°C
When a sample of warm water is mixed with a sample of cool water,
The energy amount going out of the warm water is equal to the energy amount going into the cool water. This means:
<h3>Qlost = Qgain</h3>
However,
Q = (mass) (ΔT) (Cp)
Cp = Specific heat of water = 4.184 J/Kg°C
So,
(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)
We start by calling the final, ending temperature 'x.' Keep in mind that BOTH water samples will wind up at the temperature we are calling 'x.' Also, make sure you understand that the 'x' we are using is FINAL temperature. This is what we are solving for.
The warmer water goes down from to 105°C to x, so this means its Δt equals 105°C − x. The colder water goes up in temperature, so its Δt equals x − 25℃
Substituting the values,
(10)( 105°C − x)(4.184) = (25)(x − 25℃)(4.184)
Solving for x, we get
x = 47.85°C
Therefore, The final temperature of the water mixture is 47.85°C.
Answer:
Pb²⁺(aq) --> Ni²⁺(aq)
Explanation:
The equation of the reaction is given as;
Ni(s) + Pb(NO₃)₂(aq) --> Pb(s) + Ni(NO₃)₂(aq)
In writing the ionic equation, we break the aqueous compound into ions. The solid and liquid compounds are ignored.
We have;
Pb²⁺(aq) + NO₃²⁻(aq) --> Ni²⁺(aq) + NO₃²⁻(aq)
Canceling the spectator ions;
Pb²⁺(aq) --> Ni²⁺(aq)
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