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3 years ago

HELP I NEED THIS ANSWERED

Mathematics

2 answers:

Lemur [1.5K]3 years ago

8 0

-2xy-1 not equivalent
16x+14y-1 not equivalent
2x-18x+14y-19 not equivalent
-16x+14y-1. Equivalent and simplified fully
9-16x+14y-10. Equivalent but not simplified fully
2x-18x+14y-1. Equivalent but not simplified fully

chubhunter [2.5K]3 years ago

4 0

Let me look at this hmm OK so they want each square to fit in the bottom boxes right

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Plz Help Meee!!!!! >.<

lora16 [44]

The answer is: the light rays refract toward a central axis.

5 0

3 years ago

What is the inverse of y=pi/2+sin x

Alekssandra [29.7K]

Answer:

$f^{-1}(x)=\sin ^{-1}(x-\frac{\pi}{2})$

Step-by-step explanation:

The given function is

$y=\frac{\pi}{2}+\sin x$

To find the inverse of this function, we interchange x and y.

$x=\frac{\pi}{2}+\sin y$

we now solve for y.

$x-\frac{\pi}{2}=\sin y$

Take the sine inverse of both sides to obtain;

$\sin ^{-1}(x-\frac{\pi}{2})=y$

Hence the inverse of the given function is;

$f^{-1}(x)=\sin ^{-1}(x-\frac{\pi}{2})$

where $\frac{\pi}{2}-1\le x\le \frac{\pi}{2}+1$

6 0

3 years ago

Read 2 more answers

Solve for x. 2x + 5 = x - 8

Gemiola [76]

2x+5=x-8
-x on both sides
x+5=8
-5 on both sides
x=-13

7 0

3 years ago

A number line going from 1 to 13. 1 dot is above 1. 3 dots are above 2. 1 dot is above 3. 3 dots are above 4. 1 dot is above 5.

aliina [53]

Answer:

Answer: C) The mean will increase more than the median, but both will increase.

Step-by-step explanation:

I got it right on the test review.

5 0

3 years ago

Read 2 more answers

Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi

Leona [35]

Answer:

The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Step-by-step explanation:

Explanation:-

Given equation is

$2cosx-\sqrt{3} =0 for 0$

$2cosx =\sqrt{3}$

Dividing '2' on both sides, we get

$cos x =\frac{\sqrt{3} }{2}$

$cos x = cos(\frac{\pi }{6})$

General solution of cos θ = cos ∝ is θ = 2nπ±∝

Now The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

put n=0

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Put n=1

$x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}$

$x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}$

put n=2

$x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}$

$x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}$

And so on

But given 0 < x< 2π

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

6 0

3 years ago