Answer:
S varies partly directly as M and Q.
S=C.
S=KMQ+C.
For the first one...
speed=80,m=220,Q=30.
80=K20×30+C.
80=600K+C......(I).equation one.
For the second one....
speed=60,m=300,Q=40.
60=K300×40+C.
60=12000K+C.....(ii). equation two.
Minus eqtn(I) from eqtn(ii).
80=600K+C.
- 60=12000K+C.
K=0.01754~0.018.
Substitute K=0.018 into eqtn(I).
80=600K+C
80=600×0.018+C.
80=10.8+C.
C=80-10.8=69.2.
The relation is S=0.018MQ+69.2
when speed is 100 and mass is 250 find the volume.
100=0.018×250×Q+69.2.
100=4.5Q+69.2.
4.5Q=100-69.2
4.5Q=30.8.
Q=30.8/4.5.
Q=6.8~7litres.
421/10= 42.1 vans since you can’t bring a 0.1 van you’ll have to bring a whole extra van so 43 vans
answer: one person will be in the partially full van
Answer:
x = 2
Step-by-step explanation:
Let's solve your equation step-by-step.
2.5(6x−4)=10+4(1.5+0.5x)
Step 1: Simplify both sides of the equation.
2.5(6x−4)=10+4(1.5+0.5x)
(2.5)(6x)+(2.5)(−4)=10+(4)(1.5)+(4)(0.5x)(Distribute)
15x+−10=10+6+2x
15x−10=(2x)+(10+6)(Combine Like Terms)
15x−10=2x+16
15x−10=2x+16
Step 2: Subtract 2x from both sides.
15x−10−2x=2x+16−2x
13x−10=16
Step 3: Add 10 to both sides.
13x−10+10=16+10
13x=26
Step 4: Divide both sides by 13.
x=2
Answer:
14 feet
Step-by-step explanation:
There are 3 feet in 1 yard, so 36 feet in 12 yards. The remaining ribbon will be the original amount less the amount used.
36 - 22 = 14 . . . . feet remaining
Answer:

Step-by-step explanation:
Given





Required

The total numbe of candy is:


This probability is calculated as:

For each, we have:

Take LCM



